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我試圖以編程方式使用Spring Social進行推送 - 我已經創建了一個Twitter應用程序，我爲其生成了OAuth訪問令牌，但我無法配置Spring社交本身的方式，它實際上可以推文。 配置我已經是這樣的：如何使用Spring Social以編程方式使用Spring Social進行編程
ConnectionFactoryRegistry registry = new ConnectionFactoryRegistry();
registry.addConnectionFactory(new TwitterConnectionFactory(CONSUMER_KEY, CONSUMER_SECRET));
JdbcUsersConnectionRepository jdbcUsersConnectionRepository = new JdbcUsersConnectionRepository(dataSource, registry, Encryptors.noOpText());
ConnectionRepository connectionRepository = jdbcUsersConnectionRepository.createConnectionRepository("ServerFaultBest");
Twitter twitterApi = connectionRepository.getPrimaryConnection(Twitter.class).getApi();
但由於沒有第一正在做連接，我得到：
Caused by: org.springframework.social.connect.NotConnectedException: Not connected to provider 'twitter'
at org.springframework.social.connect.jdbc.JdbcConnectionRepository.getPrimaryConnection(JdbcConnectionRepository.java:151) ~[spring-social-core-1.0.2.RELEASE.jar:na]
我甚至嘗試手動配置TwitterTemplate：
TwitterTemplate twitterTemplate = new TwitterTemplate(CONSUMER_KEY, CONSUMER_SECRET, ACCESS_TOKEN, ACCESS_TOKEN_SECRET);
twitterTemplate.timelineOperations().updateStatus("First programatic tweet with Spring Social");
但我得到：
java.lang.IllegalStateException: Connection not obtained from this manager
at org.apache.http.util.Asserts.check(Asserts.java:34)
at org.apache.http.impl.conn.tsccm.ThreadSafeClientConnManager.releaseConnection(ThreadSafeClientConnManager.java:252)
at org.apache.http.impl.conn.AbstractClientConnAdapter.abortConnection(AbstractClientConnAdapter.java:338)
at org.apache.http.impl.client.DefaultRequestDirector.abortConnection(DefaultRequestDirector.java:1119)
at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:590)
at org.apache.http.impl.client.AbstractHttpClient.doExecute(AbstractHttpClient.java:858)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:76)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:97)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:58)
at org.springframework.social.support.HttpComponentsClientHttpRequest.executeInternal(HttpComponentsClientHttpRequest.java:81)
at org.springframework.social.support.AbstractBufferingClientHttpRequest.executeInternal(AbstractBufferingClientHttpRequest.java:48)
at org.springframework.http.client.AbstractClientHttpRequest.execute(AbstractClientHttpRequest.java:49)
at org.springframework.http.client.InterceptingClientHttpRequest$RequestExecution.execute(InterceptingClientHttpRequest.java:91)
at org.springframework.social.oauth1.OAuth1RequestInterceptor.intercept(OAuth1RequestInterceptor.java:48)
at org.springframework.http.client.InterceptingClientHttpRequest$RequestExecution.execute(InterceptingClientHttpRequest.java:81)
at org.springframework.http.client.InterceptingClientHttpRequest.executeInternal(InterceptingClientHttpRequest.java:67)
at org.springframework.http.client.AbstractBufferingClientHttpRequest.executeInternal(AbstractBufferingClientHttpRequest.java:46)
at org.springframework.http.client.AbstractClientHttpRequest.execute(AbstractClientHttpRequest.java:49)
at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:483)
at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:460)
at org.springframework.web.client.RestTemplate.postForObject(RestTemplate.java:309)
at org.springframework.social.twitter.api.impl.TimelineTemplate.updateStatus(TimelineTemplate.java:138)
at org.springframework.social.twitter.api.impl.TimelineTemplate.updateStatus(TimelineTemplate.java:126)
我猜測它必須是一個簡單的配置步驟，我失蹤了 - 例如，我可以通過curl命令發送推文很好。 任何想法可能會失去這種配置？
謝謝。
Eugen。