我正在處理一個筆記應用程序,從而將添加的筆記顯示在listView
中。 我包含一個搜索欄作爲其中一個菜單項,以便在用戶嘗試搜索時過濾各個筆記。 現在,我已經實現了我的listView
的可過濾功能,但它不能按預期工作。當用戶開始輸入字母時,它不會自動過濾。在SearchView上實現自動過濾器android
用戶必須通過點擊設備上的輸入按鈕來手動執行搜索功能,即使searchView
爲空,listView
項目也不會再出現。 如何確保在用戶開始鍵入字母時自動完成搜索功能,就像大多數搜索功能一樣?
// menumain.xml
<menu xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
tools:context=".MainActivity">
<item
android:id="@+id/search"
android:orderInCategory="100"
app:actionViewClass= "android.support.v7.widget.SearchView"
app:showAsAction="ifRoom"
android:icon="@drawable/ic_search"
android:title="@string/search" />
</menu>
//Main Activity
@Override
public boolean onQueryTextSubmit(String query) {
return false;
}
@Override
public boolean onQueryTextChange(String query) {
na.getFilter().filter(query);
if (!query.equals("")) {
na.getFilter().filter(query);
nb.getFilter().filter(query);
} else {
mListNotes.setAdapter(na);
mGridNotes.setAdapter(nb);
}
return false;
}
}
// Note.java
public class Note implements Serializable {
private long mDateTime; //creation time of the note
private String mTitle; //title of the note
private String mContent; //content of the note
public Note(long dateInMillis, String title, String content) {
mDateTime = dateInMillis;
mTitle = title;
mContent = content;
}
public void setDateTime(long dateTime) {
mDateTime = dateTime;
}
public void setTitle(String title) {
mTitle = title;
}
public void setContent(String content) {
mContent = content;
}
public long getDateTime() {
return mDateTime;
}
public String getTitle() {
return mTitle;
}
public String getContent() {
return mContent;
}
}
// Note List Adapter
class NoteListAdapter extends ArrayAdapter<Note> implements Filterable{
List<Note> objects;
private List<Note> mStringFilterList;
Filter filter;
private static final int WRAP_CONTENT_LENGTH = 5;
public NoteListAdapter(Context context, int resource, List<Note> objects) {
super(context, resource, objects);
this.objects = objects;
this.mStringFilterList = objects;
}
@Override
public int getCount() {
return objects.size();
}
@Nullable
@Override
public Note getItem(int position) {
return objects.get(position);
}
@Override
public long getItemId(int position) {
return position;
}
@Override
public Filter getFilter() {
filter = new Filter() {
@Override
protected FilterResults performFiltering(CharSequence constraint) {
ArrayList<Note> tempList= new ArrayList<>();
FilterResults results = new FilterResults();
if (constraint != null && objects != null) {
for(Note singleNote : objects) {
if(singleNote.getTitle().contains(constraint))
tempList.add(singleNote);
}
results.values = tempList;
results.count = tempList.size();
}
return results;
}
@Override
protected void publishResults(CharSequence constraint, FilterResults results) {
objects = (ArrayList<Note>) results.values;
notifyDataSetChanged();
}
};
return filter;
}
}
return convertView;
}
}
請在會告訴你現在的搜索查看 –
作品的每個字符的用戶類型篩選結果,但我如何'onQueryTextChange'方法過濾當searchView爲空時,讓listview項目恢復正常?我需要一個刷新邏輯,使項目回來時,沒有文字在SearchView – Benfight
請在onQueryTextChange – Benfight