我有這個簡單的查詢,但它不是生產我想要的結果...希望你能幫助:總和DATEDIFF和group by
結果是:
Construction 2
Construction 3
Emergency Funds 4
Housing 5
Seniors Services 9
Seniors Services 185
我要的是:
Construction 5
Emergency Funds 4
Housing 5
Seniors Services 194
SELECT T.NAME, SUM(DATEDIFF (HH,T.DATE_DUE,T.DATE_START))as Donation_Hours FROM TASKS T
GROUP BY t.name, T.DATE_DUE,T.DATE_START
order by name
我想你會需要發佈一些示例數據,以及... – Randy