Knockoutjs有關的foreach孩子父母

Question

我有一個包含類型和名稱地址2門陣列等等如下模型：

var model = [{"bstype":1},{"bstype":2},{"bstype":3},{"bstype":4}], 
    [{"bstype":1, "name":"John","Address":"Sample address"}, 
    [{"bstype":1, "name":"John","Address":"Sample address"}, 
    [{"bstype":3, "name":"John","Address":"Sample address"}, 
    {"bstype":2 ,"name":"John","Address":"Sample address"}]; 
    [{"bstype":2, "name":"John","Address":"Sample address"}, 
    [{"bstype":4, "name":"John","Address":"Sample address"}]; 

什麼，我想要它做的是創建的列表：

類似於

I am not sure about this part how to implement it that is why it was gibberish. 
    bstype":1 will have a view of following 
    [{"bstype":1, "name":"John","Address":"Sample address"}, 
    [{"bstype":1, "name":"John","Address":"Sample address"}, 
    bstype"2: will have a view of following 
    {"bstype":2 ,"name":"John","Address":"Sample address"}]; 
    [{"bstype":2, "name":"John","Address":"Sample address"}, 
    bstype":3 has only one 
    [{"bstype":3, "name":"John","Address":"Sample address"}, 

等等等等。

我正在使用淘汰賽我檢查了網站，它只討論關於foreach但不知道如何訪問子元素。

我希望這是有道理的。

由於

Answer 1

我把他們分開兩個變種項第一個包含在所述第一陣列的第二的第二陣列。完成後，我使用第一個數組根據bstype循環4次。然後使用$ .root.secondarray循環遍歷第二個項目。 謝謝大家。

Answer 2

的helper方法以兩個數組組合成你有相同鍵來完成：

var model = [{"bstype":1},{"bstype":2},{"bstype":3},{"bstype":4}]; 

var modelChildren = [{"bstype":1, "name":"John","Address":"Sample address"}, 
    {"bstype":1, "name":"John","Address":"Sample address"}, 
    {"bstype":3, "name":"John","Address":"Sample address"}, 
    {"bstype":2 ,"name":"John","Address":"Sample address"}, 
    {"bstype":2, "name":"John","Address":"Sample address"}, 
    {"bstype":4, "name":"John","Address":"Sample address"}]; 

這種方法會給你一個新的數組匹配bstype「分組依據」：

var result = model.map(function(elem) 
      { 
       return { 
        bstype: elem.bstype, 
        children: modelChildren.filter(function(childElem) { 
         return childElem.bstype == elem.bstype; 
        }) 
       }; 
      });