我壓縮串PHP 5.4.4-14+deb7u7
使用的zlib壓縮在java中不工作
$cdat = gzcompress($dat, 9);
http://php.net/manual/en/function.gzcompress.php
然後在安卓/ JAVA我想解壓,從這裏開始: Android: decompress string that was compressed with PHP gzcompress()
我正在使用:
public static String unzipString(String zippedText) {
String unzipped = null;
try {
byte[] zbytes = zippedText.getBytes("ISO-8859-1");
// Add extra byte to array when Inflater is set to true
byte[] input = new byte[zbytes.length + 1];
System.arraycopy(zbytes, 0, input, 0, zbytes.length);
input[zbytes.length] = 0;
ByteArrayInputStream bin = new ByteArrayInputStream(input);
InflaterInputStream in = new InflaterInputStream(bin);
ByteArrayOutputStream bout = new ByteArrayOutputStream(512);
int b;
while ((b = in.read()) != -1) {
bout.write(b);
}
bout.close();
unzipped = bout.toString();
} catch (IOException e) {
}
return unzipped;
}
但是當我嘗試它時,它解壓縮成一個空字符串,當在android下載的壓縮字符串非常長。
下載的串像
x�͜{o�8�a`�= �!�����[��K!(6c�E�$��]�)�HF��F\!����ə���L�LNnH]Lj٬T��M���f�'�u#�*_�7'�S^�w��*kڼn�Yޚ�I��e$.1C��~�ݟ��F�A�_Mv_�R͋��ܴ�Z^L���sU?A���?��ZVmֽ6��>�B��C�M�*����^�sٸ�j����������?�"_�j�ܣY�E���h0�g��w[=&�D �oht=>�l�?��Po";`.�e�E�E��[���������sq��0���i]��������zUL�O{П��ժ�k��b�.&7��-d1_��ۣ�獮�y���=F��K!�rC�{�$����c�&9ޣH���n�x�
有誰知道問題是什麼?
謝謝。
public static Pair<String,Integer> GetHTTPResponse(String url, List<NameValuePair> urlparameters) {
String responseVal = null;
int responseCode = 0;
try {
HttpParams httpParameters = new BasicHttpParams();
int timeoutConnection = TIMEOUT_SECONDS * 1000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
int timeoutSocket = TIMEOUT_SECONDS * 1000;
HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
HttpClient client = new DefaultHttpClient(httpParameters);
HttpPost httppost = new HttpPost(url);
httppost.setEntity(new UrlEncodedFormEntity(urlparameters));
HttpResponse response = client.execute(httppost);
responseCode = response.getStatusLine().getStatusCode();
BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
responseVal = Common.GetStringFromBufferedReader(rd);
Log.d("SERVER", responseVal);
}
catch (Exception e) {
responseCode = 0;
}
if (responseVal != null) {
responseVal = Common.unzipString(responseVal);
}
return new Pair<String, Integer>(responseVal, responseCode);
}
它是二進制的而不是'String'。 – 2014-11-09 07:10:35
那麼我該如何解決這個問題? – omega 2014-11-09 07:11:45
發佈您如何從PHP獲得響應;當你將它轉換爲String時,你可以將它從二進制文件改爲字符數據。 – 2014-11-09 07:13:28