PHP插入MySql

Question

我想從表單插入數據到MySQL數據庫我有一個像下面的例子中的表格。

表格示例

複選框| Dropdown

複選框| Dropdown

複選框| Dropdown

複選框| Dropdown

所有的表和控件都從數據庫中填充。我只想從複選框被選中的下拉列表中插入值。到目前爲止，只有當第一個下拉列表不是空的時候，所有的複選框才能正常工作。用於插入

PHP代碼：

 <?php 
      //$c = checkbox array which is generated from mysql db data 
       $c = $_POST['check']; 
//$n = dropdown array which is generated from mysql db data 
       $n = $_POST['nivel']; 
     //count the amount of checkboxes checked to use in for loop 
       $camount = count($c); 
     //count the amount of dropdowns which have a value selected should be equal to $camount but it is not 
       $namount = count($n); 
        ?> 



       <?php 



          for($i = 0; $i <$camount; $i++) 
          { 

              //insert row into table for each checked checkbox 
              $d = new Disciplina_Estudiante(); 
              $d->idestudiante = $estudiante->id; 
              $d->iddisciplina =$c[$i]; 

    //this is supposed to get the values from the dropdowns that are not empty 
              $d->idnivel = $n[$i]; 


              $d->save();    
          } 


      html markup: 
      <div class="col-md-4"> 

            <table class="table table-bordered table-condensed table-hover" > 
            <thead style="background-color: #f707f3;"> 
             <tr> 
             <th>Disclipina</th> 
             <th>Costo</th> 
             <th>Grupo</th> 


             </tr> 
            </thead> 
            <tbody> 
            <?php foreach ($disciplinas as $disciplina) : ?> 

            <tr> 


              <td> <input type="checkbox" id="check" value="<?php echo $disciplina->id;?>" name="check[]"><?php echo $disciplina->nombre;?></input></td> 
              <td> <?php echo $disciplina->costo;?></td> 
              <td><select class="form-control" id="nivel" name="nivel[]" > 
              <option selected value="" readonly>Seleccionar un Nivel</option>        
              <?php foreach ($niveles as $nivel) : ?> 


              <option value="<?php echo $nivel->id; ?>"> <?php echo $nivel->nombre_nivel."<br>";?></option> 




              <?php endforeach; ?> 
               </select> 
               </td> 


            </tr> 
            <?php endforeach ;?> 

            </tbody> 

            </table> 
            <br> 
              <input type="submit" class="btn btn-primary pull-right" name="submit" value="Aceptar"></input> 


            </div> 

任何幫助，將不勝感激首次發佈...請LMK如果這沒有意義

Answer 1

您的問題是，雖然只有複選框是檢查通過$_POST陣列，所有的select框被傳遞，無論用戶是否選擇了一個值。

你可以在這種情況下，做的是指數在name屬性的複選框，以便$check[]數組的索引i將匹配$nivel[]數組的索引i。像這樣：

<input type="checkbox" id="check" value="<?php echo $disciplina->id; ?>" name="check[0]" />（順便說，input s爲自閉元素。）

這將對應選擇：<select class="form-control" id="nivel" name="nivel[0]" >

然後改變你的循環像這樣一個foreach：

foreach ($c as $i => $checkbox) { 
    $d = new Disciplina_Estudiante(); 
    $d->idestudiante = $estudiante->id; 
    $d->iddisciplina = $checkbox; 

    $d->idnivel = $n[$i]; 
    $d->save(); 
} 

最後一點，請縮進你的代碼。