Objective-C的HTTP連接 - 自動釋放沒有游泳池 - 剛剛泄露

Question

我有一個HTTP POST連接方法如下圖所示：

request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:url]]; 
[request setHTTPMethod:method]; 
[request setValue:contentType forHTTPHeaderField:@"Content-Type"]; 
[request setValue:@"DataType" forHTTPHeaderField:dataType]; 

[request setValue:[NSString stringWithFormat:@"%d", [data length]] forHTTPHeaderField:@"Content-length"]; 
[request setHTTPBody:[data dataUsingEncoding:NSUTF8StringEncoding]]; 
[[NSURLConnection alloc] initWithRequest:request delegate:self]; 
response = nil; 
NSError *error = [[NSError alloc] init]; 

NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; 
[request release]; 
result = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; 
responseCode = [response statusCode]; 

[error release]; 
if(responseCode == 200) { 
    [self connectionCompletedHere]; 
} 
else 
{ 
    [self connectionFailedHere]; 
} 

它工作正常，但即時得到控制檯消息像__NSAutoreleaseNoPool（）：對象0x62c3b80類NSURL autoreleased沒有到位 - 只是泄漏。

使用泄漏的工具，我已經把範圍縮小到2線，是造成泄漏：

[[NSURLConnection alloc] initWithRequest:request delegate:self]; 

和

NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; 

我在做什麼錯？

在此先感謝

Answer 1

不分配/初始化/釋放NSError，這是一個基準參數，只是聲明它，並通過它的地址：

NSError *error; 

返工代碼：

... 
response = nil; 
NSError *error; 

NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; 
[request release]; 
result = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; 
responseCode = [response statusCode]; 

if(responseCode == 200) { 
...