使用unix時間戳在一個月內SQL計數記錄

Question

我試圖返回每個月內的記錄數並按月/年分組結果。

模式看起來是這樣的：

id title timestamp 

我一直在尋找周圍，但我期待它，我不能得到的結果。謝謝。

Answer 1

格式化時間戳，然後按它進行分組。

組的月份：

SELECT DATE_FORMAT(t.timestamp, "%Y-%m") AS "_Month", COUNT(*) 
FROM yourtable as t 
GROUP BY _Month; 

組的年份：

SELECT DATE_FORMAT(t.timestamp, "%Y") AS "_Year", COUNT(*) 
FROM yourtable as t 
GROUP BY _Year; 

如果時間戳字段存儲爲unixtime價值，只是包裝FROM_UNIXTIME()繞場：

SELECT DATE_FORMAT(FROM_UNIXTIME(t.timestamp), "%Y") AS "_Year", COUNT(*) 
FROM yourtable as t 
GROUP BY _Year; 

Answer 2

SELECT YEAR(`timestamp`) AS Y, MONTH(`timestamp`) AS M, COUNT(1) AS C 
FROM that_table 
GROUP BY YEAR(`timestamp`), MONTH(`timestamp`) 
ORDER BY YEAR(`timestamp`), MONTH(`timestamp`)