我是Java和REST編程的新手。我舉了一個例子,但我堅持上面標題中所述的例外。任何幫助/線索非常感謝。 我有傑克遜註釋和其他相關的罐子,但我認爲我仍然缺少一些罐子 - 但不知道哪些罐子。我項目中的罐子列表現在很大,因此不在此處添加列表。如何超越異常 - 「java.lang.ClassNotFoundException:com.fasterxml.jackson.core.Versioned」
我在使用帶有eclipse(Luna 4.4.1版本)的Apache Tomcat v8.0服務器。
下面是我的代碼看起來像: 1)對象/ POJO類
package com;
public class Employee {
private int id;
private String name;
private String country;
private String salary;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getCountry() {
return country;
}
public void setCountry(String country) {
this.country = country;
}
public String getSalary() {
return salary;
}
public void setSalary(String salary) {
this.salary = salary;
}
}
2)服務類
package com;
import javax.ws.rs.Consumes;
import javax.ws.rs.GET;
import javax.ws.rs.POST;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
@Path("/json/emp1")
public class JSONService {
@GET
@Path("/get")
@Produces(MediaType.APPLICATION_JSON)
public Employee getEmployeeInJSON() {
Employee emp1 = new Employee();
emp1.setId(999);
emp1.setName("JasonEmployee");
emp1.setCountry("JasonCountry");
emp1.setSalary("JasonSalary");
return emp1;
}
@POST
@Path("/post")
@Consumes("application/json")
public Response createEmployeeInJSON(Employee emp1) {
String result = "Employee created : " + emp1;
return Response.status(201).entity(result).build();
}
}
3)在web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>Rest1</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>Jersey Web Application</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>
com, com.fasterxml.jackson.jaxrs.json
</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey Web Application</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
您可能缺少JAR文件。具體來說,傑克遜核心我建議將你的項目轉換成Maven/Gradle項目,這樣你就不必自己亂用JAR文件,儘管 –
感謝你的迴應。 我有以下: 傑克遜 - 註解-2.1.2.jar \t傑克遜 - 芯2.0.5-sources.jar \t傑克遜 - 數據綁定-2.2.3.jar \t傑克遜 - JAXRS鹼基2.2.3的.jar \t傑克遜JAXRS-JSON-提供商2.2.3.jar \t傑克遜模塊JAXB的註釋-2.1.2.jar – Ravi