如何替換python中的特定字符？

Question

所以我想做一個hang子手遊戲。我有一個函數可以將你想猜測的單詞轉換爲下劃線。所以，如果你的話是房子你最終：_ _ _ _ _

然後，我有另一個功能，將該單詞中的每個字符添加到數組中。我有一個功能，可以讓你猜測，如果猜測是不正確的，它會從你身上帶走生命（我正在使用生命系統，同時找出如何實現hang子手的繪製），並將錯誤的字母添加到一個空陣列。我的程序還會檢查您是否輸入了任何不是字母或字母不重複的字符。

我唯一的問題是，我想不出一種告訴計算機的方式，如果字母在單詞中，它應該切換你的猜測字母的空白空間。所以說，如果你的話是房子，你猜字母h它應該返回：

h _ _ _ _ 

如果我使用替換功能，它取代了正確的字母每一個下劃線。對我能做什麼有任何建議？

這裏是我的代碼：

import random 
category = [('sports', 1), ('video games', 2), ('movies', 3)] 
sports = ('football', 'baseball', 'basketball') 
video_games = ('counter strike', 'doom', 'wolfenstein') 
movies = ('star wars', 'indiana jones', 'lord of the rings') 


def pick_category(): 
    print("For sports type 1, for video games type 2, for movies type 3") 
    choice = int(input("Choose a category: ")) 
    if choice == 1: 
     word = random.choice(sports) 
    elif choice == 2: 
     word = random.choice(video_games) 
    elif choice == 3: 
     word = random.choice(movies) 
    else: 
     print("Invalid input") 
    return word 
word = pick_category() 

def convert_spaces(): #Turns every letter in the word into an empty space 
    spaces = word 
    for i in range(0, len(word)): 
     if ord(word[i]) != 32: 
      spaces = spaces.replace(word[i], '_ ') 
    print(spaces) 
    return spaces 
convert_spaces() 

def word_list(): # Appends every letter of the word into an array 
    array = [] 
    for i in range(0, len(word)): 
     array.append(word[i]) 
    print(array) 
    return array 

def guess(): 
    array = [] 
    lives = 9 
    while lives != 0: 
     n = input("Guess a letter ").lower() 
     if ord(n) in range(96, 123): 
      if n in array: 
       print("That letter is already in use.") 
      elif n not in word and n not in array: 
       array.append(n) 
       lives = lives - 1 
     else: 
      print("Invalid input, try again") 
     convert_spaces() 
     print("Used letters: ", array) 
     print("Life counter: ", lives) 
    return array 
guess() 

Answer 1

繼承人的代碼。我擺脫了你的int因爲不必要的投射導致程序崩潰。爲了讓這一切看起來和工作得很好，只需重新編寫邏輯，你幾乎就在那裏。

DIFF：https://www.diffchecker.com/fsojakzh

import random 
import string 

sports = ('football', 'baseball', 'basketball',) 
video_games = ('counter strike', 'doom', 'wolfenstein',) 
movies = ('star wars', 'indiana jones', 'lord of the rings',) 


def pick_category(): 
    print("For sports type 1, for video games type 2, for movies type 3") 
    choice = input("Choose a category: ") 
    if choice == '1': 
     word = random.choice(sports) 
    elif choice == '2': 
     word = random.choice(video_games) 
    elif choice == '3': 
     word = random.choice(movies) 
    else: 
     print("Invalid input") 
    return word 


def draw(word, guesses): 
    missing = set(string.ascii_lowercase) - set(guesses) 
    masked = "".join([l if l not in missing else '_' for l in word]) 
    print(masked) 
    return masked 


def main(): 
    word = pick_category() 
    guesses = [] 
    lives = 9 

    while lives: 
     masked = draw(word, guesses) 

     if masked == word: 
      print('You won!') 
      return 0 

     n = input("Guess a letter: ").lower() 
     if n in string.ascii_lowercase: 
      if n in guesses: 
       print("That letter is already in use.") 
      elif n not in word: 
       guesses.append(n) 
       lives = lives - 1 
      else: 
       guesses.append(n) 
     else: 
      print("Invalid input, try again") 

     print("Used letters: ", ', '.join(guesses)) 
     print("Life counter: ", lives) 

    print('You lost!') 
    return 1 

if __name__ == '__main__': 
    main() 

========================老=========== =============

我會做這樣的事情：

>>> import string 
>>> secret = "this is my hangman" 
>>> guesses = ['a', 'c', 'g'] 
>>> "".join([l if l not in set(string.ascii_lowercase) - set(guesses) else '_' for l in secret]) 
'____ __ __ _a_g_a_' 
>>> guesses.append('i') 
>>> "".join([l if l not in set(string.ascii_lowercase) - set(guesses) else '_' for l in secret]) 
'__i_ i_ __ _a_g_a_' 

注意，因爲我們是做not in和string.ascii_lowercase可是沒有「」（空間）的自動處理。沒有必要爲它創建一個黑客。