1
我有這個代碼,允許用戶上傳csv文件,並且內容將顯示在GridView中,問題是,如果任何行/列爲空,我需要顯示一條錯誤消息,任何人都可以幫助我這個?我不確定使用asp.net c#因爲我是新來的。這是我的代碼:如何檢查和顯示GridView中的空列或行?
protected void btnUpload_Click(object sender, EventArgs e)
{
string strFileNameOnServer = fileUpload.PostedFile.FileName;
string fileExt =
System.IO.Path.GetExtension(fileUpload.FileName);
if (fileUpload.PostedFile != null && fileExt == ".csv")
{
try
{
//fileUpload.PostedFile.SaveAs(ConfigurationManager.AppSettings + appDataPath + "\\" + strFileNameOnServer);
fileUpload.PostedFile.SaveAs(Server.MapPath("~/Uploaded"));
//string appPath = HttpContext.Current.Request.ApplicationPath;
// string physicalPath = HttpContext.Current.Request.MapPath("~/MajorProject");
Label1.Text = "File name: " +
fileUpload.PostedFile.FileName + "<br>" +
fileUpload.PostedFile.ContentLength + " kb<br>" +
"Content type: " +
fileUpload.PostedFile.ContentType;
}
catch (Exception ex)
{
Label1.Text = "Error saving <b>" + strFileNameOnServer + "</b><br>. " + ex.Message;
}
BtnImport1.Visible = true;
Cancel.Visible = true;
fileUpload.Visible = false;
btnUpload.Visible = false;
}
else
{
Label1.Text = "Error - a file name must be specified/only csv files are allowed";
return;
}
var data = File.ReadAllLines(Server.MapPath("~/Uploaded"))
.Select(line => line.Split(','))
.Select(columns => new {GuestName = columns[0], Guest_ID = columns[1], IC_Number = columns[2]});
myGridView.DataSource = data;
myGridView.DataBind();
}
請幫忙!
謝謝!但是我應該在哪裏放置私人字符串ValuOrErrorMessage方法?對不起 – Mark20
只是把它放在btnUpload_Click方法 – kmcc049
那樣做的,但現在它在GuestName = ErrorMessage(列[0])顯示錯誤,錯誤是不能應用與索引[],這個錯誤是什麼? – Mark20