在MySql Workbench中對索引查詢

我需要編寫一個涉及子查詢和索引的查詢。所以，我想出了一個查詢，發現其具有最高的積累速度在一年中的隊名：在MySql Workbench中對索引查詢

SELECT CONCAT(team_long_name, ',', team_short_name) AS TeamName, 
     EXTRACT(YEAR FROM date) AS Year, 
     buildUpPlaySpeed 
FROM team JOIN 
    team_attributes 
    ON team.team_api_id = team_attributes.team_api_id 
WHERE 
    (buildUpPlaySpeed,team_attributes.date) in (SELECT 
      MAX(buildUpPlaySpeed),team_attributes.date 
     FROM team_attributes 
     WHERE team_attributes.date = team_attributes.date 
     group by team_attributes.date) 
ORDER BY date desc;

指標上存在日期，team_api_id，buildUpPlaySpeed列。

關於如何進一步降低成本的任何建議？

來源

2017-11-04 Ron

羅恩，似乎你可能會很新的＃1。如果問題已得到解答，您需要指出是哪個答案，即您「接受」答案。要接受「[**點擊Tick **]（https://ibb.co/ikqyO6）」以獲取更多信息，請參閱[幫助/接受]（https://stackoverflow.com/help/someone-answers） –

是的。用加入替換相關子查詢：

SELECT CONCAT (
    team_long_name 
    ,',' 
    ,team_short_name 
    ) AS TeamName 
    ,EXTRACT(YEAR FROM [DATE]) AS Year 
    ,buildUpPlaySpeed 
FROM team 
INNER JOIN team_attributes ON team.team_api_id = team_attributes.team_api_id 
INNER JOIN (
    SELECT MAX(buildUpPlaySpeed) maxbuildup 
     ,team_attributes.[DATE] 
    FROM team_attributes 
    WHERE team_attributes.[DATE] = team_attributes.DATE 
    GROUP BY team_attributes.[DATE] 
    ) x ON buildUpPlaySpeed = x.maxbuildup 
    AND team_attributes.DATE = x.[DATE] 
ORDER BY [DATE] DESC 
;

，並且對於理智的緣故，因爲這是使用SQL請不要命名列「日期」。很混亂。

來源

2017-11-04 11:36:21

謝謝它有效:) – Ron

太棒了。你會接受這個答案嗎？ –

您對此答案仍有疑問嗎？要接受答案「[**點擊Tick **]（https://ibb.co/ikqyO6）」以獲取更多信息，請參閱[help/accepting]（https://stackoverflow.com/help/someone-answers）* * ps：當你接受答案時你獲得2點聲望點** –

嘗試，這也

SELECT CONCAT(team_long_name,',',team_short_name) AS TeamName,EXTRACT(YEAR FROM DATE) AS Year,buildUpPlaySpeed 
FROM team 
INNER JOIN team_attributes ON team.team_api_id = team_attributes.team_api_id 
INNER JOIN (SELECT MAX(buildUpPlaySpeed) maxbuildup,team_attributes.DATE FROM team_attributes 
    WHERE team_attributes.DATE = team_attributes.DATE 
    GROUP BY team_attributes.DATE ) t1 
where buildUpPlaySpeed = t1.maxbuildup AND team_attributes.DATE = t1.DATE ORDER BY DATE DESC;

來源

2017-11-04 11:54:32

在MySql Workbench中對索引查詢

回答

相關問題