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我正在使用Google腳本來獲取電子郵件的正文。我試圖只保存包含在普通YouTube電子郵件中的鏈接，該電子郵件會通知您新用戶上傳的內容。我希望只使用JavaScript保存點擊郵件中包含的圖像時所遵循的鏈接。下面看到的是郵件的一部分，外觀的例子：通過電子郵件過濾掉YouTube視頻的鏈接
電子郵件的內容是這樣的：
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FatalDubstepHD has uploaded <b>Empressto - No Love [Dubstep]</b>.
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<a href="http://www.youtube.com/watch?v=zTYri0ei45Q&feature=em-uploademail" style="text-decoration:none;display:block" class="nonplayable" target="_blank">
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Empressto - No Love [Dubstep]
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by
<a href="http://www.youtube.com/user/FatalDubstepHD?feature=em-uploademail" style="font-size:13px;color:#999999;line-height:20px;text-decoration:none" target="_blank">FatalDubstepHD</a>
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● Free Download<br><a href="https://soundcloud.com/empresstoro/empressto-no-love" target="_blank">https://soundcloud.com/<WBR>empresstoro/empressto-no-love</a><br><br>● Empressto <br><a href="http://www.facebook.com/EmpreSSto" target="_blank">http://www.facebook.com/<WBR>EmpreSSto</a><br><a href="http://www.twitter.com/Empressto" target="_blank">http://www.twitter.com/<WBR>Empressto</a><br><a href="http://www.youtube.com/user/TheOfficialEmpressto" target="_blank">http://www.youtube.com/user/<WBR>TheOfficialEmpressto</a><br><br>● Fatal Dubstep<br><a href="http://www.facebook.com/FatalMusicUK" target="_blank">http://www.facebook.com/<WBR>FatalMusicUK</a><br><a href="http://www.twitter.com/FatalMusicUK" target="_blank">http://www.twitter.com/<WBR>FatalMusicUK</a><br><br>● Owner Of Fatal<br><a href="http://www.twitter.com/Mihalis_Costa" target="_blank">http://www.twitter.com/<WBR>Mihalis_Costa</a><br><br>● Contact Email/Submit Music<br><a href="mailto:[email protected]" target="_blank">[email protected]</a>
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You were sent this email because you chose to receive updates about new videos uploaded by <a href="http://www.youtube.com/user/FatalDubstepHD?feature=em-uploademail" style="text-decoration:none;color:#1c62b9" target="_blank">FatalDubstepHD</a>. If you don't want these updates anymore, you can change your preferences by visiting the <a href="http://www.youtube.com/subscription_manager" style="text-decoration:none;color:#1c62b9" target="_blank">subscription manager</a>.
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©2013 YouTube, LLC 901 Cherry Ave, San Bruno, CA 94066
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這裏的問題是，如何我篩選後的網址從這樣的電子郵件，並且它看起來像文本3D被添加到網址，這是使網站無效，所以我也需要從網址中刪除。我怎麼能做到這一點的任何想法？
編輯：
這裏是我使用的，它缺少解析數據的代碼：
function processInbox() {
// get all threads in inbox
var label = GmailApp.getUserLabelByName("Social/YouTube/Dubstep");
var doneLabel = GmailApp.getUserLabelByName("Social/YouTube/Dubstep (added)");
var messages = label.getThreads();
var max = Math.min(messages.length,1);
for(var i = 0; i < max; ++i) {
var email = messages[i].getMessages()[0];
var contents = email.getBody();
//PARSE HERE
var xml = Xml.parse(contents,true);
Logger.log(xml);
GmailApp.sendEmail('MY EMAIL', 'Xml Contents', Logger.getLog());
//messages[i].markRead();
//messages[i].removeLabel(label).addLabel(doneLabel);
}
};
EDIT2：新代碼：
function processInbox() {
// get all threads in inbox
var label = GmailApp.getUserLabelByName("Social/YouTube/Dubstep");
var doneLabel = GmailApp.getUserLabelByName("Social/YouTube/Dubstep (added)");
var messages = label.getThreads();
var max = Math.min(messages.length,5);
for(var i = 0; i < max; ++i) {
var email = messages[i].getMessages()[0];
var contents = email.getBody();
var st = contents.indexOf('<a href="http://www.youtube.com/watch?v=');
var str1 = contents.substr(st+9,80);
var end = str1.indexOf('&');
var link = str1.substring(0,end);
Logger.log(link);
GmailApp.sendEmail('EMAIL', 'Xml Contents', Logger.getLog());
Logger.clear();
//messages[i].markRead();
//messages[i].removeLabel(label).addLabel(doneLabel);
}
這種方法是不是真的使用功能在谷歌的腳本，然後是它的工作？我使用getBody（）更新了其中一封電子郵件的確切輸出。實際上是否有使用Google腳本的內置函數來獲取XML數據的方法？ – ComputerLocus 2013-03-09 22:29:38
?? XML服務是Google腳本中的默認服務......我並不真正瞭解您的評論。抱歉，如果我錯過了什麼。 – 2013-03-09 22:37:43
我添加了我目前正在使用的代碼。有沒有什麼方法可以像我現在這樣使用代碼，還是必須完全改變它來使用你的XML方法？如果我必須改變它，我會怎樣做呢？我對JavaScript和Google腳本非常陌生，所以我一直在尋找一個基本的解決方案，但我想這不會是一個？ – ComputerLocus 2013-03-09 22:42:03