正如上面@Devs,你必須通過一些貼圖參數(地名或座標),以google.html您頁。我修改了招呼頁面:
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>
<body>
<address>
Sector 75-Noid...
</address>
<a href="google.html?q=France"><button type="button">view on map</button></a>
<address>Delhi</address>
<a href="google.html?q=Delhi"><button type="button">view on map</button></a>
</body>
</html>
正如你所看到的,google.html您的聯繫現在有「Q」的查詢字符串參數,這將在google.html您頁面中使用:
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<script src="http://jashkenas.github.com/coffee-script/extras/coffee-script.js"></script>
<meta charset=utf-8 />
<title>Welcome to JS Bin</title>
<meta name="viewport" content="width=device-width">
<link href='http://fonts.googleapis.com/css?family=Doppio+One' rel='stylesheet' type='text/css'>
<script type="text/javascript">
$(document).ready(function() {
$("address").each(function() {
var embed ="<iframe width='425' height='350' frameborder='0' scrolling='no' marginheight='0' marginwidth='0' src='https://maps.google.com/maps?&q="+ encodeURIComponent(getParameterByName('q')) +"&output=embed'></iframe>";
$(this).html(embed);
});
function getParameterByName(name, url) {
if (!url) {
url = window.location.href;
}
name = name.replace(/[\[\]]/g, "\\$&");
var regex = new RegExp("[?&]" + name + "(=([^&#]*)|&|#|$)"),
results = regex.exec(url);
if (!results) return null;
if (!results[2]) return '';
return decodeURIComponent(results[2].replace(/\+/g, " "));
}
});
</script>
</head>
<body>
<address>Australia</address>
</body>
</html>
你可以嘗試在工作演示here
你從來沒有通過任何地圖參數或座標來google.html您 –
那麼,如何解決這個問題請告訴我 – neha
的鏈接是死在了這個問題,對於依靠任何問題的危險在外部鏈接上。這確實意味着它需要關閉。請嘗試儘可能保持您的問題獨立,以限制所需的關閉和刪除數量。 – halfer