2017-03-04 83 views
0

我知道這個主題有很多問題,但我似乎找不到與我的場景有關的任何問題。DBContext在控制器中生成,仍然得到兩個對象之間的關係...不同的ObjectContext對象

即時得到「兩個對象之間的關係不能被定義,因爲它們連接到不同的ObjectContext對象」上Inventory CurrentInventory = db.Inventories.Find(injection.InventoryID);

這工作很我第一次運行它,並隨後嘗試都失敗。

我不明白我是如何獲得不同的上下文對象。

我的控制器:

public class InventoriesController : Controller 
{ 
    private ApplicationDbContext db = new ApplicationDbContext(); 

    // GET: Inventories/Edit 
    public ActionResult Edit() 
    { 
     return View(db.Inventories.ToList()); 
    } 

    // POST: Inventories/Edit/5 
    // To protect from overposting attacks, please enable the specific properties you want to bind to, for 
    // more details see http://go.microsoft.com/fwlink/?LinkId=317598. 
    [HttpPost] 
    [ValidateAntiForgeryToken] 
    public ActionResult Edit(List<Inventory> inventory) 
    { 
     //List<Inventory> inventory 
     if (inventory == null) 
     { 
      return new HttpStatusCodeResult(HttpStatusCode.BadRequest); 
     } 

     foreach (Inventory injection in inventory) 
     { 
      Inventory CurrentInventory = db.Inventories.Find(injection.InventoryID); 
      CurrentInventory.Date = DateTime.Now; 
      CurrentInventory.Quantity = injection.Quantity; 
      CurrentInventory.LastChangedBy = System.Web.HttpContext.Current.GetOwinContext().GetUserManager<ApplicationUserManager>().FindById(System.Web.HttpContext.Current.User.Identity.GetUserId()); 
     } 

     if (ModelState.IsValid) 
     { 
     // db.Entry(inventory).State = EntityState.Modified; 
      db.SaveChanges(); 
      return RedirectToAction("Index"); 
     } 
     return View(EntityState.Modified); 
    } 
} 

編輯:

我回到了一個較爲單一更新方法,只是爲了看看是否會有幫助。我仍然得到相同的錯誤。所以我將其與其他控制器之一進行了比較,修改了Edit方法,並注意到我沒有使用.Find()方法,而是反覆對它們記錄自己並返回所需的對象。做這件事時,問題解決了。

// GET: Inventories/Edit/5 
     public ActionResult Edit(int? id) 
     { 
      if (id == null) 
      { 
       return new HttpStatusCodeResult(HttpStatusCode.BadRequest); 
      } 
      Inventory inventory = db.Inventories.Find(id); 
      ViewData["Id"] = System.Web.HttpContext.Current.GetOwinContext().GetUserManager<ApplicationUserManager>().FindById(System.Web.HttpContext.Current.User.Identity.GetUserId()); 

      if (inventory == null) 
      { 
       return HttpNotFound(); 
      } 
      return View(inventory); 
     } 

     // POST: Inventories/Edit/5 
     // To protect from overposting attacks, please enable the specific properties you want to bind to, for 
     // more details see http://go.microsoft.com/fwlink/?LinkId=317598. 
     [HttpPost] 
     [ValidateAntiForgeryToken] 
     public ActionResult Edit([Bind(Include = "InventoryID,Quantity,LastChanged,Date")] Inventory inventory) 
     { 
      Inventory oldInventory = null; 
      foreach (var a in db.Inventories) 
      { 
       if (a.InventoryID == inventory.InventoryID) 
       { 
        oldInventory = a; 
       } 
      } 

      if (oldInventory == null) 
      { 
       return HttpNotFound(); 
      } 

      if (ModelState.IsValid) 
      { 
       //db.Entry(inventory).State = EntityState.Modified; 
       TryUpdateModel(oldInventory); 
       db.SaveChanges(); 
       return RedirectToAction("Index"); 
      } 
      return View(inventory); 
     } 

後續問題:

是否.Find()方法在實施創建另一個的DbContext使返回的對象本身是從完全不同的環境?

回答

0

對控制器中的私有上下文進行迭代並返回所需的對象而不是使用.Find()方法解決了我的問題,儘管我並不太熱衷於此原因。

+0

你應該做庫存CurrentInventorydb.Inventories.Find(x => x.InventoryID == injection.InventoryID); –

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