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我想比較,如果n1-10其中之一是=框 然後寫nx1和ny1等等...... 我該怎麼做才能比較它們更快。 下面的方式將需要幾年從我Lua比較多個整數
box=readString('[[[[[_name]+11c]+670]+394]+2fc]+1c',20)
n1=readString('[_player]+184',20)
n2=readString('[_player]+f94',20)
n3=readString('[_player]+1da4',20)
nx1= readInteger('[_player]+48d8')
nx2= readInteger('[_player]+56e8')
nx3= readInteger('[_player]+64f8')
ny1= readInteger('[_player]+48dc')
ny2= readInteger('[_player]+56ec')
ny3= readInteger('[_player]+64fc')
if box =n1 or n2 or n3 --lets say n1=box
then writeInteger('[_player]+28c',n1x)
writeInteger('[_player]+28c',n1y)
if box =n1 or n2 or n3 --lets say n2=box
then writeInteger('[_player]+28c',n2x)
writeInteger('[_player]+28c',n2y)