如何獲得登錄用戶名和插入在笨PHP

Question

在另一個表我是一個博客網頁，我會被插入從管理博客panel.while插入博客到數據庫中，我需要插入的管理員用戶名以及進入的數據庫中如何獲取管理員用戶名並插入到博客表中。

控制器：

function addblogs() 
{ 
    $this->load->library('form_validation'); 
    $this->form_validation->set_error_delimiters('<br /><span class="error"> ','</span>'); 
    $this->form_validation->set_rules('blog_title','Blog Title'); 
    $this->form_validation->set_rules('description','Blog Description');   
    if($this->form_validation->run()== FALSE) 
    {  

    $data['mainpage']='blogs'; 
    $data['mode']='add'; 
    $this->load->view('templates/template',$data); 
    } 
    else 
    { 
     $this -> blogs_model -> insertblogs(); 
     $this->flash->success('<h2>blogs Added Successfully!</h2>'); 
     redirect('blogs'); 
    } 
} 

型號：

function insertblogs() 
{ 
    $username = $_SESSION['name']; 

    $title=$this->input->post('blog_title'); 
    $result = str_replace(" ", "-", $title); 

    $data=array(

    'blog_title'=>$this->input->post('blog_title'), 
    'blogtitle'=>$result, 
    'description'=>$this->input->post('description'), 
    'user'=>$username 
    ); 
       $this->db->insert('blogs',$data);   
    } 
} 

查看：

<?php 
     $form_attributes = array('name'=>'adds', 'id'=>'adds', 'enctype' => "multipart/form-data"); 
     echo form_open('blogs/addblogs',$form_attributes); 
    ?> 

    <div class="element"> 
     <label for="blogtitle"><font color ="black">Blog Title</font></label> 
     <input class="text err" type="text" name="blog_title" id="blog_title" value="<?php echo set_value('blog_title');?>"/>    
    </div> 
     <div class="element"> 
     <label for="description"><font color ="black">Blog Description</font></label> 
     <textarea name="description" id="myArea1" rows="4" cols="173"></textarea> 
    </div> <br/>   
    <div align="center"> 
      <input type="submit" id="submit" value="Submit" /> 
    </div> 
    <div class="clear"></div> 
    <?php echo form_close();?> 

登錄控制器：

if($this->session->userdata('admin_logged_in')){ 
     $data['admin_details'] = $this->session->userdata('admin_logged_in'); 
     $data['records']=$this->career_model->get_jobs_list(); 
     $data['mode'] = "all"; 
     $data['mainpage'] = "career"; 
     $this->load->view('templates/template', $data); 
    } 
    else{ 
     $this->load->view('login'); 
    }  

登錄型號：

<?php 
class login_model extends MY_Model 
{ 
function login_user($user_name = '', $password=''){ 

    $userdetails = array(
    'user_name' => $user_name, 
    'password' => md5($password), 
    ); 
    $this->db->where($userdetails); 
    $query = $this->db->get('login_details'); 
    if($query->num_rows()): 
     $user = $query->result(); 
     $sess_arry = array(
      'user_id' => $user[0]->user_id, 
      'name' => $user[0]->name 
     );   
     $this->session->set_userdata('admin_logged_in', $sess_arry);  //add admin details to session 
     return true; 
    else: 
     return false; 
    endif; 
} 
} 

Answer 1

您可以將某些改變你在insertblogs()方式類似型號：

$this->load->library('session'); 
$logged_data = $this->session->userdata('admin_logged_in'); 

$user_id = $logged_data['user_id']; 
$user_name = $logged_data['name']; 

$username = $user_name;//$_SESSION['name']; 

Answer 2

您可以通過獲得登錄用戶名：

$username = $this->session->userdata('username'); 

現在你可以使用這個$username將其插入到數據庫中，也可以執行一些其他功能。