Subprocess.Popen即使在超時的情況下

Question

我使用subprocess.Popen和Popen.communicate運行一個超時的過程獲取輸出，類似於給出的建議是這樣一個問題：

Subprocess timeout failure

因此，我現在用的是下面的代碼：

with Popen(["strace","/usr/bin/wireshark"], stdout=subprocess.PIPE,stderr=subprocess.PIPE, preexec_fn=os.setsid) as process: 
    try: 
     output = process.communicate(timeout=2)[0] 
     print("Output try", output) 
    except TimeoutExpired: 
     os.killpg(process.pid, signal.SIGINT) # send signal to the process group 
     output = process.communicate()[0] 
     print("Output except",output) 
return output 

而且我得到以下輸出：

Output except b'' 

和b''作爲返回值。

即使TimeoutExpired異常被引發，我怎樣才能獲得進程的輸出（輸出直到它被殺死）？

Answer 1

Popen對象有kill方法，爲什麼不使用它呢？一個進程被殺死後，你可以讀取它的stdout。這是否工作？

with Popen(["strace","/usr/bin/wireshark"], stdout=subprocess.PIPE,stderr=subprocess.PIPE, preexec_fn=os.setsid) as process: 
    try: 
     output = process.communicate(timeout=2)[0] 
     print("Output try", output) 
    except TimeoutExpired: 
     process.kill() 
     output = process.stdout.read().decode() 
     print("Output except",output) 
return output