2017-09-23 83 views
-2

星期假設我得到了一週的一天,這獲取明天與日期(「L」)PHP

$monday = date("l"); 

其作品,但現在,我想獲得未來兩天像

$date = ("Y-m-d"); 
$tuesday = date('l', strtotime('+1 day',$dateaa)); 
$wednesday = date('l', strtotime('+3 day',$dateaa)); 

,但我得到了Monday Monday當我贊同$tuesday$wednesday

+0

你還沒有把你的代碼放在'$ dateaa'中。 –

回答

0

試試這個

<?php 
$days = array("Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"); 
$today = date('w'); 
$nextTwoDay = $today + 2; 
if ($nextTwoDay > 6) $nextTwoDay = $nextTwoDay - 6; 
echo $days[$nextTwoDay]; 
?> 
+0

謝謝@Piotr Grudniewski – Lio

1

確定嗎?

$dateaa = strtotime('last sunday'); 
echo $wednesday = date('l', strtotime('+3 day', $dateaa)); // wednesday 

$dateaa = strtotime('last monday'); 
echo $thursday = date('l', strtotime('+3 day', $dateaa)); // thursday