如何分配兩個SQL查詢的結果？

Question

SELECT * FROM(
     (SELECT 
      count(DISTINCT RECEPIENT_ID) as NoOfUsers, 
      TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') as accDate 
     FROM 
      ALRT_PLATFORM_ALRT_HSTRY 
     where 
      APPL_CD like 'EBP' and 
      ALRT_RSPNS_FROM_CLIENT_ID like 'BB' 
      group by TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') 
     ) b, 

     (SELECT 
      count(DISTINCT RECEPIENT_ID) as NoOfUsers, 
      TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') as accDate 
     FROM 
      ALRT_PLATFORM_ALRT 
     where 
      APPL_CD like 'EBP' and 
      ALRT_RSPNS_FROM_CLIENT_ID like 'BB' 
      group by TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') 
     ) f 
     ) 

此查詢按以下格式返回數據：

NOOFUSERS    ACCDATE NOOFUSERS    ACCDATE  
---------------------- ---------- ---------------------- ---------- 
2      2009-12-21 1      2010-03-01 
2      2009-12-21 2      2010-03-02 
2      2009-12-21 1      2010-03-03 
1      2009-12-23 1      2010-03-01 

是有可能俱樂部兩個表的reuslt： 很期待的數據是這種格式：

NOOFUSERS    ACCDATE  
---------------------- ---------- 
2      2009-12-21 
1      2009-12-23 
1      2010-01-02 
1      2010-01-04 //till here its table one data 
1      2010-03-01 //from here its table TWO data 
2      2010-03-02 
1      2010-03-03 

謝謝:)

Answer 1

使用UNION ALL而不是後選列會將後續的UNION ALL語句附加到原始選擇。小心你需要每個選擇語句中的相同數量的列。

UNION ALL確保組合結果不被排序/混合（第一個查詢在第二個之前返回）。常規的UNION可以/將混合/混合/排序結果。

SELECT 
      count(DISTINCT RECEPIENT_ID) as NoOfUsers, 
      TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') as accDate 
     FROM 
      ALRT_PLATFORM_ALRT_HSTRY 
     where 
      APPL_CD like 'EBP' and 
      ALRT_RSPNS_FROM_CLIENT_ID like 'BB' 
      group by TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') 


UNION ALL 

     SELECT 
      count(DISTINCT RECEPIENT_ID) as NoOfUsers, 
      TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') as accDate 
     FROM 
      ALRT_PLATFORM_ALRT 
     where 
      APPL_CD like 'EBP' and 
      ALRT_RSPNS_FROM_CLIENT_ID like 'BB' 
      group by TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') 

Answer 2

也許你必須使用UNION運算符？ http://dev.mysql.com/doc/refman/5.5/en/union.html

SELECT count(DISTINCT RECEPIENT_ID) as NoOfUsers, 
      TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') as accDate 
     FROM 
      ALRT_PLATFORM_ALRT_HSTRY 
     where 
      APPL_CD like 'EBP' and 
      ALRT_RSPNS_FROM_CLIENT_ID like 'BB' 
      group by TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') 

UNION  
    SELECT count(DISTINCT RECEPIENT_ID) as NoOfUsers, 
      TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') as accDate 
     FROM 
      ALRT_PLATFORM_ALRT 
     where 
      APPL_CD like 'EBP' and 
      ALRT_RSPNS_FROM_CLIENT_ID like 'BB' 
      group by TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') 

Answer 3

嘗試聯合聲明

（選擇1）聯盟（選擇2）

SELECT 
     count(DISTINCT RECEPIENT_ID) as NoOfUsers, 
     TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') as accDate 
    FROM 
     ALRT_PLATFORM_ALRT_HSTRY 
    where 
     APPL_CD like 'EBP' and 
     ALRT_RSPNS_FROM_CLIENT_ID like 'BB' 
     group by TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') 

UNION 

    SELECT 
     count(DISTINCT RECEPIENT_ID) as NoOfUsers, 
     TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') as accDate 
    FROM 
     ALRT_PLATFORM_ALRT 
    where 
     APPL_CD like 'EBP' and 
     ALRT_RSPNS_FROM_CLIENT_ID like 'BB' 
     group by TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') 

Answer 4

可以使用二者結合起來的結果UNION

例子：

select col1, col2 
from table1 
where... 

UNION 

select col1, col2 
from table2 
where... 

Answer 5

依我之見，你沒有任何連接兩套（b和f）之間的條件。因此請使用UNION或UNION ALL。 Refer here。

Answer 6

如果您有要求經常在一起查詢這些表，那麼您可以考慮使用視圖。

create view alrt_platform_alrt_all as 
    select * from alrt_platform_alrt 
union all 
    select * from alrt_platform_alrt_hstry; 

這則允許您查詢數據，象這樣：

select 
    count(distinct recepient_id), 
    TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD') as accDate 
from alrt_platform_alrt_all 
where appl_cd like 'EBP' 
    and alrt_rspns_from_client_id like 'BB' 
group by TO_CHAR(ACTN_TAKE_DATA_TM,'YYYY-MM-DD');