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你能告訴我這個怎麼了? 它拋出錯誤如何解決這個子查詢錯誤?
子查詢返回的值超過1。當子查詢遵循=,!=,<,< =,>,> =或當子查詢用作表達式時,這是不允許的。
什麼意思使用({?SUB_ALLOC_PARM}))
我猜它的參數值正確嗎?
select distinct LFS_LFS as DN
, LFS_VONNR
, LZL_REFNR
, AGR_TEXT
, LFS_KNR as Store
, LFS_DATOK
, FIL_INDEX as Store_name
, LAN_TEXT as COUNTRY
, LZL_MENGE as Qty
, ANS_NAME1 AS 'Customer Name'
, ANS_NAME2 AS 'Customer Address line 1'
, ANS_STRASSE AS 'Customer Address line 2'
, ANS_STRASSE_2 AS 'Customer Address line 3'
, ANS_ORT AS 'City'
, ANS_TITEL AS 'State'
, LAN_TEXT AS 'Country'
, ANS_PLZ AS 'PostCode'
, (select FIL_NUMMER
from FUTURA..V_FILIALEN as HO
where HO.FIL_LAND = STORE.FIL_LAND
and HO.FIL_MANDANT = 1
and HO.FIL_ART = 0
) as HO_BRANCH
from FUTURA..V_LIEFHEAD,
FUTURA..V_ARTIKEL,
FUTURA..V_ART_KOPF,
FUTURA..V_LIEFZEIL,
FUTURA..V_LAGER as BR5,
FUTURA..V_FILIALEN as STORE,
FUTURA..V_ANSCHRIF,
FUTURA..V_LAND
where AGR_MANDANT = ART_MANDANT
and AGR_WARENGR = ART_WARENGR
and AGR_ABTEILUNG = ART_ABTEILUNG
and AGR_TYPE = ART_TYPE
and AGR_GRPNUMMER = ART_GRPNUMMER
and LZL_REFNR = ART_REFNUMMER
and ART_MANDANT = LFS_MANDANT
and LFS_LFS = LZL_LFS and LFS_MANDANT = LZL_MANDANT
and LFS_MANDANT = 1
and LZL_REFNR <> 0
and LZL_REFNR = BR5.LAG_REFNUMMER
and LZL_MANDANT = BR5.LAG_MANDANT
and BR5.LAG_MANDANT = 1
and BR5.LAG_FILIALE = LFS_VONNR
and FIL_MANDANT = LZL_MANDANT
and FIL_NUMMER = LFS_KNR
and LAN_MANDANT = FIL_MANDANT
and LAN_NUMMER = FIL_LAND
AND ANS_TYP = 2 -- branches
AND ANS_COUNT = 1 -- sequence 1
AND ANS_MANDANT = FIL_MANDANT
AND ANS_NUMMER = FIL_NUMMER
and LFS_LFS IN (
select distinct PVG_LIEFERSCHEIN
from FUTURA..V_PVERFIL
where PVG_NUMMER IN ({?SUB_ALLOC_PARM})
)
order by
LFS_KNR
呃,我不會重新格式化爲零接受評級... – 2011-05-03 04:59:29
這些列寫入哪些語言?如果是英文,則需要對其表格結構進行重大更名。呃...難以閱讀,甚至不會嘗試。 – Mikecito 2011-05-03 05:12:51
顯然它是德文的,裏面有很多縮寫,這使得它仍然很難閱讀。 – Alex 2011-05-03 06:47:09