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我正在做一個hang子手遊戲,當我運行代碼除了贏得一線以外的所有工作。 長度是來自當前猜測的字的字母數量,並且長度是實際數量長度需要匹配。如果我有一個5個字母的單詞長度最終將是大約9,這就是我需要幫助。爲什麼python添加更多的變量比需要?
import turtle
import random
w1 = "battery"
w2 = "report"
w3 = "beach"
w4 = "mayor"
w5 = "score"
w6 = "overeat"
w7 = "load"
w8 = "social"
w9 = "honor"
w10 = "risk"
turns = 10
guesses = ''
err = 0
gennum = random.randint(1, 10)
if gennum == 1:
usedw = w1
elif gennum == 2:
usedw = w2
elif gennum == 3:
usedw = w3
elif gennum == 4:
usedw = w4
elif gennum == 5:
usedw = w5
elif gennum == 6:
usedw = w6
elif gennum == 7:
usedw = w7
elif gennum == 8:
usedw = w8
elif gennum == 9:
usedw = w9
elif gennum == 10:
usedw = w10
wn = turtle.Screen()
draw = turtle.Turtle()
length = len(usedw)
lengthr = int(0)
print("Welcome to hangman your word is", length, "letters long.")
while turns > 0:
guess = input("Choose a character: ")
guesses += guess
for char in usedw:
if char in guesses:
print (char,)
lengthr += 1
else:
err += 1
if err == 1:
draw.goto(0,0)
draw.down()
draw.goto(200,0)
elif err == 2:
draw.up()
draw.goto(0,0)
draw.down()
draw.goto(0,200)
elif err == 3:
draw.up()
draw.goto(0,200)
draw.down()
draw.goto(100,200)
elif err == 4:
draw.up()
draw.goto(100,200)
draw.down()
draw.goto(100,150)
elif err == 5:
draw.up()
draw.goto(100,100)
draw.down()
draw.circle(25)
elif err == 6:
draw.up()
draw.goto(100,100)
draw.down()
draw.goto(100,50)
elif err == 7:
draw.up()
draw.goto(75,90)
draw.down()
draw.goto(125,90)
elif err == 8:
draw.up()
draw.goto(100,50)
draw.down()
draw.goto(75,35)
elif err == 9:
draw.up()
draw.goto(100,50)
draw.down()
draw.goto(125,35)
print("You loose.")
break
if lengthr == length:
print ("You won!")
您可能想將單詞放在列表中,並使用['random.choice'](https://docs.python.org/2/library/random.html#random.choice)來選擇它們。 –