如何從JSON從文件內容獲取標籤數據

Question

$json = file_get_contents('module=API&method=Referrers.getReferrerType&format=json&period=day&date=yesterday&disableLink=1&idSite=3'); 
$data = json_decode($json,true); 

JSON數據：

[{"label":"Direct Entry","nb_uniq_visitors":526,"nb_visits":593,"nb_actions":768,"nb_users":0,"max_actions":32,"sum_visit_length":83153,"bounce_count":513,"nb_visits_converted":0,"segment":"referrerType==direct"},{"label":"Search Engines","nb_uniq_visitors":230,"nb_visits":235,"nb_actions":631,"nb_users":0,"max_actions":71,"sum_visit_length":52233,"bounce_count":150,"nb_visits_converted":0,"segment":"referrerType==search","idsubdatatable":2},{"label":"Websites","nb_uniq_visitors":7,"nb_visits":7,"nb_actions":20,"nb_users":0,"max_actions":5,"sum_visit_length":835,"bounce_count":1,"nb_visits_converted":0,"segment":"referrerType==website","idsubdatatable":3}] 

我試圖以顯示引用類型的每個標籤。

1. 直接進入

2. 搜索引擎

3. 網站

$data[0]->label;不起作用

$data->label;不起作用

$data->label[0];不起作用

Answer 1

你可以試試這個，因爲你要轉換的JSON數據關聯數組（嵌套），通過傳遞true到json_decode方法的第二個參數：

$json = "[{\"label\":\"Direct Entry\",\"nb_uniq_visitors\":526,\"nb_visits\":593,\"nb_actions\":768,\"nb_users\":0,\"max_actions\":32,\"sum_visit_length\":83153,\"bounce_count\":513,\"nb_visits_converted\":0,\"segment\":\"referrerType==direct\"},{\"label\":\"Search Engines\",\"nb_uniq_visitors\":230,\"nb_visits\":235,\"nb_actions\":631,\"nb_users\":0,\"max_actions\":71,\"sum_visit_length\":52233,\"bounce_count\":150,\"nb_visits_converted\":0,\"segment\":\"referrerType==search\",\"idsubdatatable\":2},{\"label\":\"Websites\",\"nb_uniq_visitors\":7,\"nb_visits\":7,\"nb_actions\":20,\"nb_users\":0,\"max_actions\":5,\"sum_visit_length\":835,\"bounce_count\":1,\"nb_visits_converted\":0,\"segment\":\"referrerType==website\",\"idsubdatatable\":3}]"; 

$data = json_decode($json, true); 
print_f($data[0]['label']); 

希望這有助於！

Answer 2

您將true傳遞給第二個參數json_decode()。這使得它返回一個關聯數組。因此，您可以簡單地使用這樣的數據：

$data[0]["label"]