2017-07-03 91 views
0

我有一些存儲在表中的XML。我需要能夠採取這個XML並拉出某些值。如何使用Oracle返回XML列XMLTABLE

我已經寫了一些代碼來嘗試並返回<ns1:Int32/>標記的值,但至今我還沒有能夠返回結果。

我在網上發現了幾個使用XMLTABLE函數的例子,但不幸的是這些例子中有很多使用比我更簡單的XML

XML

<Rule Priority="0" Description="Description 1" Active="True" ReevaluationBehavior="Always" Name="Name 1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/workflow"> 
    <Rule.Condition> 
     <RuleExpressionCondition Name="{p3:Null}" xmlns:p3="http://schemas.microsoft.com/winfx/2006/xaml"> 
      <RuleExpressionCondition.Expression> 
       <ns0:CodeBinaryOperatorExpression Operator="BooleanAnd" xmlns:ns0="clr-namespace:System.CodeDom;Assembly=System, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089"> 
        <ns0:CodeBinaryOperatorExpression.Right> 
         <ns0:CodeBinaryOperatorExpression Operator="GreaterThanOrEqual"> 
          <ns0:CodeBinaryOperatorExpression.Right> 
           <ns0:CodePrimitiveExpression> 
            <ns0:CodePrimitiveExpression.Value> 
             <ns1:Int32 xmlns:ns1="clr-namespace:System;Assembly=mscorlib, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089">11</ns1:Int32> 
            </ns0:CodePrimitiveExpression.Value> 
           </ns0:CodePrimitiveExpression> 
          </ns0:CodeBinaryOperatorExpression.Right> 
         </ns0:CodeBinaryOperatorExpression> 
        </ns0:CodeBinaryOperatorExpression.Right> 
       </ns0:CodeBinaryOperatorExpression> 
      </RuleExpressionCondition.Expression> 
     </RuleExpressionCondition> 
    </Rule.Condition> 
</Rule> 

SQL

SELECT Rules2.* 
FROM RULES Rules1, 
XMLTABLE 
(
    XMLNAMESPACES 
    (
     'http://schemas.microsoft.com/winfx/2006/xaml' AS "p3", 
     'clr-namespace:System;Assembly=mscorlib, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' AS "ns0", 
     'clr-namespace:System;Assembly=mscorlib, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' AS "ns1", 
     DEFAULT 'http://schemas.microsoft.com/winfx/2006/xaml/workflow' 
    ) 
    , 
    '/Rule/RuleExpressionCondition/CodeBinaryOperatorExpression/CodePrimitiveExpression' 
    PASSING XMLPARSE(CONTENT Rules1.RULE WELLFORMED) 
    COLUMNS "Int" INT PATH 'ns1:Int32' 
) 
Rules2 
; 

任何幫助,這是極大的讚賞。

+0

你是什麼意思的價值「標籤」?你的意思是價值11? – mathguy

+0

是的,在這個例子中,我的意思是11. – Freddie2025

回答

3

ns0的名稱空間定義中的URL錯誤。和xmltable中的錯誤路徑。您可以使用簡短版本。或提供完整路徑。 /Rule/Rule.Condition/RuleExpressionCondition/RuleExpressionCondition.Expression/ns0:CodeBinaryOperatorExpression/ns0:CodeBinaryOperatorExpression.Right/ns0:CodeBinaryOperatorExpression/ns0:CodeBinaryOperatorExpression.Right/ns0:CodePrimitiveExpression/ns0:CodePrimitiveExpression.Value

SELECT Rules2.* 
FROM xmls Rules1, 
XMLTABLE 
(
    XMLNAMESPACES 
    (
     'http://schemas.microsoft.com/winfx/2006/xaml' AS "p3", 
     'clr-namespace:System.CodeDom;Assembly=System, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' AS "ns0", 
     'clr-namespace:System;Assembly=mscorlib, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' AS "ns1", 
     DEFAULT 'http://schemas.microsoft.com/winfx/2006/xaml/workflow' 
    ) 
    , 
    '//ns0:CodePrimitiveExpression.Value' 
    PASSING XMLPARSE(CONTENT Rules1.RULE WELLFORMED) 
    COLUMNS "Int" INT PATH 'ns1:Int32' 
) 
Rules2 
+0

太好了,非常感謝 – Freddie2025

+1

使用簡短版本('//'會導致性能低下。'//'應該被避免,除非你正在搜索一個遞歸結構 –

0

我認爲問題是,你的搜索表達式是

/Rule/RuleExpressionCondition/CodeBinaryOperatorExpression/CodePrimitiveExpression

該表達式缺少多個節點,對吧?