Mysql的子查詢與點心，加入和GROUP BY

如何使子查詢和總與個人用戶的印記？目前，我只能得到第一個用戶的標誌，我怎麼能得到每個用戶的標誌？這裏是小提琴http://sqlfiddle.com/#!9/d6d68/3

數據集...

SELECT * FROM positions; 
+----+-----------+---------------+------------+---------------+---------------------+---------------------+ 
| id | code_name | display_name | category | default_merit | created_at   | updated_at   | 
+----+-----------+---------------+------------+---------------+---------------------+---------------------+ 
| 1 | K01  | Chairman  | College |    8 | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 | 
| 2 | K02  | Vice Chairman | College |    6 | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 | 
| 3 | K03  | Treasurer  | College |    6 | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 | 
| 4 | K04  | Secretary  | College |    6 | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 | 
| 5 | K05  | Committee  | College |    4 | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 | 
| 6 | K06  | Participator | College |    1 | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 | 
| 7 | U01  | Chairman  | University |   10 | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 | 
| 8 | U02  | Vice Chairman | University |    8 | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 | 
| 9 | U03  | Treasurer  | University |    8 | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 | 
| 10 | U04  | Secretary  | University |    8 | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 | 
| 11 | U05  | Committee  | University |    5 | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 | 
| 12 | U06  | Participator | University |    2 | 2016-06-08 10:30:55 | 2016-06-08 10:30:55 | 
+----+-----------+---------------+------------+---------------+---------------------+---------------------+ 

SELECT * FROM records; 
+----+---------+-------------+--------+---------+---------------+-----------------+------------+------------+------------+---------------------+---------------------+ 
| id | user_id | position_id | finish | approve | recordable_id | recordable_type | deleted_at | created_by | approve_by | created_at   | updated_at   | 
+----+---------+-------------+--------+---------+---------------+-----------------+------------+------------+------------+---------------------+---------------------+ 
| 1 |  1 |   1 |  1 |  1 |    1 | App\Event  | NULL  |   1 |   1 | 2016-06-08 10:30:55 | 2016-06-08 10:30:55 | 
| 2 |  1 |   2 |  1 |  0 |    2 | App\Event  | NULL  |   1 |   1 | 2016-06-08 10:30:55 | 2016-06-08 10:30:55 | 
| 3 |  2 |   2 |  1 |  0 |    2 | App\Event  | NULL  |   1 |   1 | 2016-06-08 10:30:55 | 2016-06-08 10:30:55 | 
| 4 |  2 |   2 |  1 |  0 |    2 | App\Club  | NULL  |   1 |   1 | 2016-06-08 10:30:55 | 2016-06-08 10:30:55 | 
| 5 |  2 |   2 |  1 |  0 |    1 | App\Sub_Event | NULL  |   1 |   1 | 2016-06-08 10:30:55 | 2016-06-08 10:30:55 | 
| 6 |  3 |   2 |  1 |  0 |    2 | App\Club  | NULL  |   1 |   1 | 2016-06-08 10:30:56 | 2016-06-08 10:30:56 | 
| 7 |  2 |   3 |  1 |  0 |    2 | App\Club  | NULL  |   1 |   1 | 2016-06-08 10:30:56 | 2016-06-08 10:30:56 | 
+----+---------+-------------+--------+---------+---------------+-----------------+------------+------------+------------+---------------------+---------------------+ 

SELECT * FROM users; 
+----+----------------+--------+-------------------------+----------+----------------+------------+---------------------+---------------------+-----------+----------+--------+-----------+-------------+-----------+------------+ 
| id | name   | matrix | email     | password | remember_token | deleted_at | created_at   | updated_at   | attention | resident | banned | meritbook | must_inlist | protected | last_login | 
+----+----------------+--------+-------------------------+----------+----------------+------------+---------------------+---------------------+-----------+----------+--------+-----------+-------------+-----------+------------+ 
| 1 | Lim Yoong Kang | 47408 | [email protected] | Szha6... | NULL   | NULL  | 2016-06-08 10:30:53 | 2016-06-08 10:31:05 |   0 |  1 |  0 |   0 |   0 |   0 | NULL  | 
| 2 | Admin John  | 00001 | [email protected]  | HYSPq... | NULL   | NULL  | 2016-06-08 10:30:53 | 2016-06-08 10:30:53 |   1 |  1 |  0 |   0 |   0 |   0 | NULL  | 
| 3 | Moderator Wong | 00002 | [email protected]  | fvxWS... | NULL   | NULL  | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 |   1 |  1 |  0 |   0 |   0 |   0 | NULL  | 
| 4 | Student Tai | 00003 | taileepeng[email protected] | ihdF6... | NULL   | NULL  | 2016-06-08 10:30:54 | 2016-06-08 10:30:54 |   1 |  1 |  0 |   0 |   0 |   0 | NULL  | 
+----+----------------+--------+-------------------------+----------+----------------+------------+---------------------+---------------------+-----------+----------+--------+-----------+-------------+-----------+------------+

和期望的結果

+--------+----------------+-------+ 
| matrix | name   | total | 
+--------+----------------+-------+ 
|  1 | Admin John  |  0 | 
|  2 | Moderator Wong |  0 | 
|  3 | Student Tai |  0 | 
|  4 | Lim Yoong Kang |  8 | 
+--------+----------------+-------+

，我目前使用

SELECT 
    `users`.`matrix`, 
    `users`.`name`, 
    (SELECT SUM(positions.default_merit) 
    FROM `users` 
    INNER JOIN `records` ON `records`.`user_id` = `users`.`id` 
    INNER JOIN `positions` ON `positions`.`id` = `records`.`position_id` 
    WHERE `records`.`finish` = '1' AND `records`.`approve` = '1' AND `users`.`deleted_at` IS NULL) AS total 
FROM `users` 
GROUP BY `users`.`matrix` 
HAVING total >= 0 

LIMIT 100

SQL查詢

來源

2016-06-08 YoongKang Lim

請注意，沒有ORDER BY的LIMIT是相當無意義的 - 即使使用了GROUP BY子句。這本手冊詳細討論了這個問題（但不是很清楚）。 – Strawberry

@Strawberry感謝您的建議。我將來會使用Limit with OrderBy。我太新手了，非常感謝你的幫助。 –

位置表中沒有user_id。同樣，在記錄表中的display_name。 – Strawberry

我想到的是選擇在這一切default_merits，符合條件的一個表，然後組它的用戶。這應該會導致一個表，其中的所有用戶只有自己default_merits的總和：

如果再加入所有你有你應該讓你在找什麼用戶的總數。

SELECT 
    `users`.`matrix`, 
    `users`.`name`, 
    IFNULL(`totals`.`total`, 0) as `total` 
FROM `users` 
    LEFT JOIN (
    SELECT 
    `users`.`matrix`, 
    SUM(positions.default_merit) as `total` 
    FROM `users` 
    LEFT JOIN `records` ON `records`.`user_id` = `users`.`id` 
    LEFT JOIN `positions` ON `positions`.`id` = `records`.`position_id` 
WHERE `records`.`finish` = 1 AND `records`.`approve` = 1 AND `users`.`deleted_at` IS NULL 
GROUP BY `users`.`matrix`) AS `totals` ON `users`.`matrix` = `totals`.`matrix`

來源

2016-06-08 15:27:00 Fuzzzzel

感謝你的幫助。您的查詢效果很好，但總共爲0的用戶也會過濾。任何方法來保存它們？ –

沒錯，沒有想到這一點。您可以用查詢包含所有用戶的查詢並加入總計。然後你添加IFNULL（總數，0）。我會修改我的答案。 – Fuzzzzel

您的IFNULL和包裹的查詢正在工作！謝謝 –

Mysql的子查詢與點心，加入和GROUP BY

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