如何做一個簡單的方法來檢查用戶是否已經存在於註冊表中？

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我已經做了一個項目用戶在Android登錄，我如何檢查一個簡單的代碼就像一個PHP（哈哈）如果用戶已經存在，然後做一個敬酒。你有什麼要求嗎？如何做一個簡單的方法來檢查用戶是否已經存在於註冊表中？

這裏是我的Java

protected String doInBackground(String... args) { 

    List<NameValuePair> params = new ArrayList<NameValuePair>();   params.add(new BasicNameValuePair("nama", namauser.getText().toString())); 
    params.add(new BasicNameValuePair("fakunit", spPropellant.getSelectedItem().toString())); 
    params.add(new BasicNameValuePair("notelp", notelpon.getText().toString())); 
    params.add(new BasicNameValuePair("email", email.getText().toString())); 
    //params.add(new BasicNameValuePair("npwp", username.getText().toString())); 
    params.add(new BasicNameValuePair("password", password.getText().toString())); 

      JSONObject json = jsonParser.makeHttpRequest(url_insert, 
      "POST", params); 

    // check log cat fro response 
    Log.d("Create Response", json.toString()); 

    // check for success tag 
    try { 
     int success = json.getInt(TAG_SUCCESS); //ambil success value yang dikirim php 

     if (success == 1) { // cek jika variable success = 1, berarti registrasi berhasil 
      runOnUiThread(new Runnable() { 
       public void run() { 
        Toast.makeText(getApplicationContext(), "Register Success. Please Log in!", Toast.LENGTH_LONG).show(); 
       }}); 

      Intent i = new Intent(Register.this, Login.class); 
      startActivity(i); 
      finish(); 
     } 
     else { 
      runOnUiThread(new Runnable() { 
       public void run() { 
        Toast.makeText(getApplicationContext(), "Register GAGAL.", Toast.LENGTH_LONG).show(); 
       }}); 

      Intent i = new Intent(Register.this, Register.class); 
      startActivity(i); 
     } 
    } catch (JSONException e) { 
     e.printStackTrace(); 
    } 

    return null; 
} 


protected void onPostExecute(String file_url) { 
    // dismiss the dialog once done 
    dialog.dismiss(); 
}

這PHP代碼寄存器 phpregister

來源

2017-10-17 Rizki Deddy Susanto