BASH不同退出級別的多個退出函數

Question

如何在bash中使用多個退出陷阱？ 說我想在退出-1上的退出代碼1 和退出-2退出代碼2

function on-exit1 { 
     echo "do stuff here if code had exit status 1" 
     } 
    function on-exit2 { 
     echo "do stuff here if code had exit status 2" 
     } 
    ..... 

    trap on-exit1 EXIT # <--- what do i do here to specify the exit code to trap 
    trap on-exit2 EXIT # <--- what do i do here to specify the exit code to trap 
    ..... 
    some bashing up in here 
    blah...blah 
     exit 1 # do on-exit1 
    else blah blah 
     exit 2 # do on-exit2 
    else blah blah 
     exit N # do on-exitNth 

Answer 1

類似下面的代碼示例應該工作：

exit_check() { 
    # bash variable $? contains the last function exit code 
    # will run the function on_exit1 if status exit is 1, on_exit2 if status exit is 2, ... 
    on_exit$? 
} 
trap exit_check EXIT 

Answer 2

如果你真的想用陷阱運行，試試這個：

#!/usr/bin/env bash 

function finish { 
    echo "exitcode: $?" 
} 

trap finish EXIT 

read -n 1 -s exitcode 
exit $exitcode 

但是，如@ 123所示，您可以調用您的退出函數，無需在此處「濫用」陷阱。

下次嘗試提供工作示例;）。