Ajax無法正確解析數據？

瞭解我，我可能做錯了什麼，但我看看如何解析數據從Javascript到PHP看起來像使用Ajax，它看起來不錯，但它不想通過發送數據並更新它我的數據庫。Ajax無法正確解析數據？

發生的只是一個對話框，裏面沒有任何東西。

AJAX：

$.ajax({ 
     url: 'updateCredits.php', 
     type: 'GET', 
     data: { 
      credits: totalcash 
     }, 
     success: function(data){ 
      alert(data); 
     } 
    });

PHP：

<?php 

require 'steamauth/steamauth.php'; 
include ('steamauth/userInfo.php'); 
include('mysql/config.php'); 

if(isset($_SESSION['steamid'], $_GET["credits"])) { 
    $credits = $_GET['credits']; 
    mysqli_query($db,"UPDATE set credits = credits + '".$credits."' WHERE steamid = '".$steamprofile['steamid']."'"); 
} else { 
echo 'An Error has occurred, this is either due to you not being logged in or something went wrong!'; 

} 

?>

來源

2017-10-17 Samuel Stubbings

你期望發生的？你沒有在成功上回應任何事情。另外你的代碼是非常非常非常脆弱的[SQL注入]（https://www.owasp.org/index.php/SQL_Injection） – ntzm

側面說明：您應該使用PUT如果更新操作 –

這是工作正常。代碼中的空警報意味着，在數據庫中最可能沒有錯誤和數據。 –

你是不是從PHP返回任何東西片斷成功

<?php require 'steamauth/steamauth.php'; 
include ('steamauth/userInfo.php'); 
include('mysql/config.php'); 
if(isset($_SESSION['steamid'], $_GET["credits"])) 
{ 
    $credits = $_GET['credits']; mysqli_query($db,"UPDATE set credits = credits + '".$credits."' WHERE steamid = '".$steamprofile['steamid']."'"); 
echo 'Success fully updated'; 
} else { echo 'An Error has occurred, this is either due to you not being logged in or something went wrong!'; } ?>

來源

2017-10-17 19:25:12 GaneshSreeju

Ajax無法正確解析數據？

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