顯示從MySQL查詢返回的記錄

Question

我無法顯示發送給用戶的消息。

假設用戶是我的表「消息」中的id列，我將如何顯示發送給該用戶的消息？

session_start(); 
require "bidcon.php"; 
$userfinal=$_SESSION['username']; 
$id = mysql_query("SELECT id FROM searchengine") or die(mysql_error()); 

// get the messages from the table. 
$get_messages = mysql_query(
    "SELECT messages_id FROM messages 
    WHERE to_user='$id' ORDER BY messages_id DESC") 
    or die(mysql_error()); 

$get_messages2 = mysql_query(  
    "SELECT * FROM messages   
    WHERE to_user='$id' ORDER BY messages_id DESC")  
    or die(mysql_error()); 

$num_messages = mysql_num_rows($get_messages); 
// display each message title, with a link to their content 
echo '<ul>'; 

for($count = 1; $count <= $num_messages; $count++) 
{ 
    $row = mysql_fetch_array($get_messages2); 

Answer 1

我不是很清楚你爲什麼需要兩個不同的查詢。但是你的主要問題是如何顯示記錄。你會做while循環裏面，像這樣：

$rs = mysql_query("SELECT id FROM searchengine") or die(mysql_error()); 
$rec = mysql_fetch_assoc($rs); 
$id = $rec['id']; 

// get the messages from the table. 
$get_messages = mysql_query(
    "SELECT * FROM messages 
    WHERE to_user='$id' ORDER BY messages_id DESC") 
    or die(mysql_error()); 
$num_messages = mysql_num_rows($get_messages); 

// display each message title, with a link to their content 
echo '<ul>'; 
while($row=mysql_fetch_assoc($get_messages)){ 
    // do stuff with each row 
    echo "<li>".$row['somefield']."</li>"; 
} 
echo '</ul>'; 

Answer 2

此：

$id = mysql_query("SELECT id FROM searchengine"); 

將使$id一個MySQL的資源，不是你要找的整數/字符串。

而是執行此操作：

$res = mysql_query("SELECT id FROM searchengine"); 
$id = mysql_result($res, 0);