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正如標題已經規定，我需要從MySQL發送數據通過PHP擅長用一些過濾即值大於0PHP和MySQL到Excel
我喜歡this code偉大的工程......
<?php
/*******EDIT LINES 3-8*******/
$DB_Server = "localhost"; //MySQL Server
$DB_Username = "username"; //MySQL Username
$DB_Password = "password"; //MySQL Password
$DB_DBName = "databasename"; //MySQL Database Name
$DB_TBLName = "tablename"; //MySQL Table Name
$filename = "excelfilename"; //File Name
/*******YOU DO NOT NEED TO EDIT ANYTHING BELOW THIS LINE*******/
//create MySQL connection
$sql = "Select * from $DB_TBLName";
$Connect = @mysql_connect($DB_Server, $DB_Username, $DB_Password) or die("Couldn't connect to MySQL:<br>" . mysql_error() . "<br>" . mysql_errno());
//select database
$Db = @mysql_select_db($DB_DBName, $Connect) or die("Couldn't select database:<br>" . mysql_error(). "<br>" . mysql_errno());
//execute query
$result = @mysql_query($sql,$Connect) or die("Couldn't execute query:<br>" . mysql_error(). "<br>" . mysql_errno());
$file_ending = "xls";
//header info for browser
header("Content-Type: application/xls");
header("Content-Disposition: attachment; filename=$filename.xls");
header("Pragma: no-cache");
header("Expires: 0");
/*******Start of Formatting for Excel*******/
//define separator (defines columns in excel & tabs in word)
$sep = "\t"; //tabbed character
//start of printing column names as names of MySQL fields
for ($i = 0; $i < mysql_num_fields($result); $i++) {
echo mysql_field_name($result,$i) . "\t";
}
print("\n");
//end of printing column names
//start while loop to get data
while($row = mysql_fetch_row($result))
{
$schema_insert = "";
for($j=0; $j<mysql_num_fields($result);$j++)
{
if(!isset($row[$j]))
$schema_insert .= "NULL".$sep;
elseif ($row[$j] != "")
$schema_insert .= "$row[$j]".$sep;
else
$schema_insert .= "".$sep;
}
$schema_insert = str_replace($sep."$", "", $schema_insert);
$schema_insert = preg_replace("/\r\n|\n\r|\n|\r/", " ", $schema_insert);
$schema_insert .= "\t";
print(trim($schema_insert));
print "\n";
}
?>
...如何當我試圖分開的要求值，即大於0我什麼也得不到。我試圖做的是如下：
我已經在while($row = mysql_fetch_row($result)){之後加了這個if ($row["row_name"] > "0")，在另一個例子中我工作得很好，但是這次沒有運氣。任何指針應該不勝感激。
** **停止。使用'mysqli_ *'或PDO – Jens
^這。此外，我會建議尋找使用PHPOffice/PHPExcel或PHPOffice/PHPSpreadsheet（較新） –
你的表中有一列'row_name'嗎？ – Jens