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我已經在phpmyadmin中創建了以下觸發器。如何檢索觸發器中select語句返回的多個值?
delimiter |
create trigger active after insert on event
for each row
begin
declare n int;
set n = (select follower_id from follow where circle_id=new.circle_id);
insert into activity (uid, performed_activity_id,activity_type_id) values(new.uid,new.event_id,'1');
insert into notification (sender_id,receiver_id,message)values (new.uid,n,new.title);
end;
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我在這裏得到的問題是,選擇語句更多的reture一個值。
ERROR 1242 (21000): Subquery returns more than 1 row
如何從select語句獲取多個值,以及如何通過他們插入衆所周知聲明?
但我想follower_id的所有值,並將其傳遞給通知 – 2013-03-02 11:10:09
然後我就更新答案。 – 2013-03-02 11:12:32
看到更新':D'使用'INSERT INTO ... SELECT' – 2013-03-02 11:14:34