在Orientdb上使用append和substring查詢SQL

Question

我需要從具有international_prefix和local_prefix之類的圖像的表中檢索國家/地區。

這是我做了可惜都不行測試。

SELECT * 
FROM core_phone_prefix 
WHERE (("+393925559000").asString()).left(international_prefix.append(local_prefix).length()) = international_prefix.append(local_prefix) 

Answer 1

你能與此查詢

select country from( 
    select number.left(international_prefix.append(local_prefix).length()) as a, international_prefix.append(local_prefix) as b, country from (
     select international_prefix, "+393925559000" as number, country, local_prefix from core_phone_prefix 
    ) 
) where a = b 

修訂

試試看你能在球場上local_prefix場上international_prefix（NOTUNIQUE_HASH_INDEX）和一個插入兩個指數，一個（NOTUNIQUE_HASH_INDEX）

您可以使用此查詢

select expand($a) from (select "+393925559000" as number from core_phone_prefix limit 1) 
    let $a=(select from core_phone_prefix WHERE international_prefix = $parent.current.number.left(international_prefix.length()) 
      and local_prefix = $parent.current.number.subString(international_prefix.length(),international_prefix.append(local_prefix).length())) limit -1 

讓我知道

Answer 2

嘗試這些：

有了這一個我只比較前綴

select distinct(country) as country from(select international_prefix, "+393925559000" as number, country, local_prefix from core_phone_prefix) where international_prefix=number.subString(0,international_prefix.length()) 

取而代之的是，這一個我比較international_prefix +帶有international_prefix和local_prefix的local_prefix，號碼爲

select country as country from(select international_prefix, "+393925559000" as number, country, local_prefix from core_phone_prefix) where international_prefix.append(local_prefix)=number.subString(0,international_prefix.append(local_prefix).length()) 

希望它能幫助，

讓我知道