迭代只多單字典

一個字典列表我有一個列表的字典，像這樣：迭代只多單字典

edu_options = { 'Completed Graduate School' : ['medical','litigation','specialist'...], 

      'Completed College' : ['linguistic','lpn','liberal','chicano'... ], 

      'Attended College' : ['general','inprogress','courseworktowards','continu'...],

我原來的代碼，而在分級匹配的嘗試：

for edu_level in edu_options: 
     for option in edu_options[edu_level] 

       if option in cleaned_string: 
         user = edu_level 
         return user 
        else: continue

我一個比較字符串到這些列表並返回密鑰。我想以分層的方式來做。

for edu_level in edu_options: 
     for option in edu_options[edu_level]: 

      if cleaned_string in edu_options["Completed Graduate School"]: 
        user = "Completed Graduate School" 
        return user        

      elif cleaned_string in edu_options["Completed College"]: 
        user = "Completed College" 
        return user 

      elif option in cleaned_string: 
        user = edu_level 
        return user

這些if語句適用於大多數比較str，但不會拿起幾個例子。對於第一個和第二個if語句，我只想將其與「完成的研究生院」等相應列表進行比較。有沒有辦法迭代通過只有該列表而不使用另一個for循環？類似於

Ex: string = Bachelor of Arts: Communication and Civil Service 
    cleaned_string = bachelorofartscommunicationandcivilservice 
    option = iterating through each item(str) of lists in edu_option

我想讓畢業生和大學名單首先通過，因爲他們更小，更具體。我想糾正的錯誤是edu_options中的另一個更大的列表，其中包含與str_string_string不匹配的子str。

來源

2016-09-21 pproctor

清單字符串是一個列表嗎？或者你正在查找cleanded_string中的子字符串？ –

cleared_string只是一個str，我想與ers_options列表中的strs比較 – pproctor

所以，當你說「elif option in cleaned_string」時，這個選項是一個字符串，它將在clean_string裏查找（這也是一個字符串）。這是你打算做什麼？ –

如何：

for key, val_list in edu_options.items(): 
    if key == "Completed Graduate School": 
     if cleaned_string in val_list: 
      #do something 
    #Similarly for remaining key types

這樣一來，您被限制檢查專門的密鑰類型。

來源

2016-09-21 19:18:55 karthikr

for edu_level in edu_options: 
     for option in edu_options[edu_level]: 

      if cleaned_string in edu_options["Completed Graduate School"]: 
        user = "Completed Graduate School" 
        return user        

      elif cleaned_string in edu_options["Completed College"]: 
        user = "Completed College" 
        return user 

      elif option == cleaned_string: 
        user = edu_level 
        return user

來源

2016-09-21 19:54:53

迭代只多單字典

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