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在我的應用程序中,我需要在桌面視圖單元上顯示一個或多個圖像,具體取決於它們在數據庫中的可用性。我所做的是我已經種植了四個網頁瀏覽器[顯示來自網址的圖片],並且根據其可用性隱藏或顯示這些圖片。動態顯示桌面視圖單元格上的圖像
當我完全隱藏網頁瀏覽時,可能還存在沒有圖像的情況。
但隨機滾動後我的應用程序崩潰。另外,在滾動時,它會向更舊的圖像顯示新圖像。所以,我能夠首先看到一幅圖像,然後在滾動相同的單元格之後,兩幅圖像相互引導[前一張照片的某些部分可見]等等。這可能是因爲細胞可重複使用嗎?關於這個問題的理想方式是什麼?
編輯:
我用下面的代碼:
noOfPhotos = [photos_array count];
if(noOfPhotos > 0){
commentWhenWebviewNotThere.alpha = 0.0; //Things that are not visible when images are there
noOfCommentsWhenWebviewNotThere.alpha = 0.0;
commentsLblWhenWebviewAbset.alpha = 0.0;
image1.hidden = NO;
image2.hidden = NO;
image3.hidden = NO;
image4.hidden = NO;
commentsLblWhenWebview.alpha = 1.0;
noOfComments.alpha = 1.0;
comment.alpha = 1.0;
for(NSInteger x = 0; x < noOfPhotos; x++){
photoName = [photos_array objectAtIndex:x];
NSString *urlAddress = [NSString stringWithFormat:@"%@",photoName];
NSURL *url = [NSURL URLWithString:urlAddress];
NSURLRequest *requestObj = [NSURLRequest requestWithURL:url];
if(x == 0){
image1 = [[UIWebView alloc] initWithFrame:CGRectMake(10, comment.frame.origin.y - 5, 60, 60)];
[image1 loadRequest:requestObj]; //Load the request in the UIWebView.
[self addSubview:image1];
}
else if(x == 1){
image2 = [[UIWebView alloc] initWithFrame:CGRectMake(88, comment.frame.origin.y - 5, 60, 60)];
[image2 loadRequest:requestObj]; //Load the request in the UIWebView.
[self addSubview:image2];
}
else if(x == 2){
image3 = [[UIWebView alloc] initWithFrame:CGRectMake(169, comment.frame.origin.y - 5, 60, 60)];
[image3 loadRequest:requestObj]; //Load the request in the UIWebView.
[self addSubview:image3];
}
else if(x == 3){
image4 = [[UIWebView alloc] initWithFrame:CGRectMake(251, comment.frame.origin.y - 5, 60, 60)];
[image4 loadRequest:requestObj]; //Load the request in the UIWebView.
[self addSubview:image4];
}
}
}
else{
commentWhenWebviewNotThere.alpha = 1.0; //Should be visible when images are not there
noOfCommentsWhenWebviewNotThere.alpha = 1.0;
commentsLblWhenWebviewAbset.alpha = 1.0;
commentsLblWhenWebview.alpha = 0.0;
noOfComments.alpha = 0.0;
comment.alpha = 0.0;
image1.hidden = YES;
image2.hidden = YES;
image3.hidden = YES;
image4.hidden = YES;
}
Thanx提前。
我沒有在這裏回答你的崩潰問題,但你不需要web視圖來顯示來自URL的圖像。您可以使用UIImageView並從URL設置圖像。 (UIImage * image = [UIImage imageWithData:[NSData dataWithContentsOfURL:[NSUrl NSURL URLWithString:MyURL]]];)這會容易得多。 – lukya 2010-07-20 06:51:44
另外,發佈一些代碼。這會讓你更容易知道你的應用崩潰的原因。 – lukya 2010-07-20 06:52:43
Thanx lukya你的迴應。我已經更新了我的問題。請檢查。 – neha 2010-07-20 07:01:38