在matlab中讀取數組中的文件

Question

1 :: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 
2 :: 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 
3 :: 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 1 
4 :: 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 
5 :: 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 1 
6 :: 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 
7 :: 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 
8 :: 0 0 0 0 0 0 0 0 0 0 0 1 0 0 1 0 
9 :: 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 0 
10 :: 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 1 
11 :: 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 1 
12 :: 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 

我有上面的文本文件。我想在Matlab中讀取這個文件，並且想要將文件的內容以兩列存儲在數組中。在第一列中的
序列號和其他列的16位模式如下

1  0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 
2  0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 
3  0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 1 
4  0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 
5  0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 1 
6  0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 
7 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 

任何人可以幫助我嗎？

Answer 1

如果索引是有序的像1:n（或任何其他已知的順序），您可以使用此：

fileID = fopen('bin16.txt'); 
raw = fscanf(fileID,'%s'); 
fclose(fileID); 
colon_ind = strfind(raw,'::'); 
data = table((1:numel(colon_ind)).',... 
    cell(numel(colon_ind),1),... 
    'VariableNames',{'Index','Pattern'}); 
counter = 1; 
for k = colon_ind 
    data.Pattern(counter,:) = {raw(k+2:k+17)}; 
    counter = counter+1; 
end 

，並得到這個：

data = 
    Index   Pattern  
    _____ __________________ 
    1  '0000000000000011' 
    2  '0000000000000101' 
    3  '0000000000001001' 
    4  '0000000000000110' 
    5  '0000000000010001' 
    6  '0000000000001010' 
    7  '0000000000000111' 
    8  '0000000000010010' 
    9  '0000000000001100' 
    10  '0000000000001011' 
    11  '0000000000100001' 
    12  '0000000000010100' 

如果索引列是不是命令你可以使用這樣的事情：

fileID = fopen('bin16b.txt','r'); 
raw = fscanf(fileID,'%s'); 
C = textscan(raw,'%s','delimiter','::'); 
fclose(fileID); 
N = (size(C{1},1)-1)/2; 
data = table(zeros(N,1),cell(N,1),... 
    'VariableNames',{'Index','Pattern'}); 
data.Index(1) = str2num(C{1}{1,1}); 
for k = 1:N 
    if k>1 
     data.Index(k) = str2num(C{1}{k*2-1,:}(17:end)); 
    end 
    data.Pattern(k,:) = {C{1}{k*2+1,:}(1:16)}; 
end 

獲得（與我輸入的一些任意數據）：

Index   Pattern  
_____ __________________ 
54  '0000000000000011' 
6  '0000000000000101' 
3  '0000000000001001' 
4  '0000000000000110' 
5  '0000000000010001' 
92  '0000000000001010' 
7  '0000000000000111' 
35  '0000000000010010' 
9  '0000000000001100' 
10  '0000000000001011' 
11  '0000000000100001' 
12  '0000000000010100' 

---

編輯

如果 '::' 在文件可以被刪除之前，那麼你可以使用：

text = load ('bin16b.txt', '-ascii'); 
data = table(text(:,1),text(:,2:end),... 
    'VariableNames',{'Index','Pattern'}); 

，並得到：

data = 
    Index  Pattern 
    _____ _____________ 
    54  [1x16 double] 
    6  [1x16 double] 
    3  [1x16 double] 
    4  [1x16 double] 
    5  [1x16 double] 
    92  [1x16 double] 
    7  [1x16 double] 
    35  [1x16 double] 
    9  [1x16 double] 
    10  [1x16 double] 
    11  [1x16 double] 
    12  [1x16 double] 

其中模式列中的每個單元格都是這樣的：

>> data.Pattern(1,:) 
ans = 
    Columns 1 through 14 
    0  0  0  0  0  0  0  0  0  0  0  0  0  0 
    Columns 15 through 16 
    1  1