獨立字符串值不同的變量

我通過YouTube API，讓視頻有多長拉一個字符串，字符串可以有不同的值，如：獨立字符串值不同的變量

$time = "PT1H50M20S"; (Video is 1h 50m 20s long) 
$time = "PT6M14S"; (Video is 6m 14s long) 
$time = "PT11S"; (Video is 11s long)

如何保存的小時，分鍾秒鐘在單獨的變量？上面的代碼應該給：

$time = "PT1H50M20S"; -> $h = 5, $m = 50, $s = 20 
$time = "PT6M14S"; -> $h = 0, $m = 6, $s = 14 
$time = "PT11S"; -> $h = 0, $m = 0, $s = 11

來源

2014-12-01 Muki

@ Rizier123算不了什麼，我不知道如何做到這一點。 – Muki 2014-12-01 18:27:19

您可以使用此功能，您的字符串轉換爲有效時間。

function getDuration($str){ 
    $result = array('h' => 0, 'm' => 0, 's' => 0); 
    if(!preg_match('%^PT(?:(\d+)H)?(?:(\d+)M)?(?:(\d+)S)?$%',$str, $matches)) return $result; 

    if(isset($matches[1]) && !empty($matches[1])) $result['h'] = $matches[1]; 
    if(isset($matches[2]) && !empty($matches[2])) $result['m'] = $matches[2]; 
    if(isset($matches[3]) && !empty($matches[3])) $result['s'] = $matches[3]; 

    return $result; 
}

結果：

print_r(getDuration('PT1H50M20S')); 

//Array 
//(
// [h] => 1 
// [m] => 50 
// [s] => 20 
//)

來源

2014-12-01 19:44:03

我試過'％^ PT（？：（\ d +）H）？（？：（\ d +）M）？（\ d +）S $％'。如果一段視頻長3米，那麼字符串將是「PT3M」，這是行不通的，有沒有辦法解決這個問題？編輯：我改變它爲'^ PT（？：（\ d +）H）？（？：（\ d +）M）？（？：（\ d +）S）？$'這似乎是工作，是這正確的方法？ – Muki 2014-12-01 20:12:15

現在您可以放心使用。 ;） – 2014-12-02 13:07:50

@Muki你檢查這個嗎？ – 2014-12-02 18:11:55

(\d+)(?=h\b)|(\d+)(?=m\b)|(\d+)(?=s\b)

嘗試this.Grab $1爲h，$2爲m等on.See演示。

http://regex101.com/r/vF0kU2/10

$re = "/(\\d+)(?=h\\b)|(\\d+)(?=m\\b)|(\\d+)(?=s\\b)/m"; 
$str = "\$time = \"PT1H50M20S\"; (Video is 1h 50m 20s long)\n\$time = \"PT6M14S\"; (Video is 6m 14s long)\n\$time = \"PT11S\"; (Video is 11s long)\n"; 

preg_match_all($re, $str, $matches);

來源

2014-12-01 18:29:38 vks

我試過這個，但它不起作用，匹配[1-3]沒有匹配，re不適用於字符串，比如「PT6M14S」，請看這裏：http://regex101.com/r/ aZ5fJ5/1 – Muki 2014-12-01 19:02:38

獨立字符串值不同的變量

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