讓TreePanel中顯示ExtJS的項目，如兒童

我需要顯示ExtJS的兼容項目作爲樹的JSON，這裏是它的外觀像讓TreePanel中顯示ExtJS的項目，如兒童

{ 
    text: 'Menu Root', 
    expanded: true, 
    items: [ 
      { text: 'detention', leaf: true }, 
      { text: 'homework', expanded: true, items: [ 
      { text: 'book report', leaf: true }, 
      { text: 'algebra', leaf: true} 
      ] }, 
      { text: 'buy lottery tickets', leaf: true } 
     ] 
}

如果items是children它工作正常，但與items事實並非如此。我沒有在ExtJS6文檔中找到讓Treepanel將項目視爲孩子的方法。僅供參考，這些是需要考慮的一些內容。我使用setRootNode添加這treestore

來源

2017-04-13 ducktyped

它可以通過在樹存儲配置配置defaultRootProperty缺省實現以"items"到："children"。

Ext.application({ 
 
    name: 'Fiddle', 
 

 
    launch: function() { 
 
var store = Ext.create('Ext.data.TreeStore', { 
 
    defaultRootProperty : 'items', // need change the default "children" to "items" 
 
    root: {  
 
    text: 'Menu Root', 
 
    expanded: true, 
 
    items: [ 
 
      { text: 'detention', leaf: true }, 
 
      { text: 'homework', expanded: true, items: [ 
 
      { text: 'book report', leaf: true }, 
 
      { text: 'algebra', leaf: true} 
 
      ] }, 
 
      { text: 'buy lottery tickets', leaf: true } 
 
     ] 
 
     
 
} 
 
}); 
 

 
Ext.create('Ext.tree.Panel', { 
 
    title: 'Simple Tree', 
 
    width: 200, 
 
    height: 150, 
 
    store: store, 
 
    renderTo: Ext.getBody() 
 
}); 
 

 
    } 
 
});

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來源

2017-04-13 12:44:22

讓TreePanel中顯示ExtJS的項目，如兒童

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