在codeigniter的一個表中檢索多個具有相同名稱的數據

function search_review($input, $serviceName){ 
     $ipJson = json_encode($input); 
     $this->db->select('*'); 
     $this->db->from('reviews'); 
     $this->db->where('reviewee_name', $input['reviewee_name']); 
     $query = $this->db->get(); 
     $result = $query->result(); 
     if (!empty($result)) { 
     foreach ($query->result() as $row) 
     { 
      $data['reviewer_id'] = $row->reviewer_id; 
      $data['reviewee_name'] = $row->reviewee_name; 
      $data['tournament_played_c_s'] = $row->tournament_played_c_s; 
     } 
      $data['message'] = 'Review details retrieved successfully.'; 
      $status = $this->clamo_lib->return_status('success', $serviceName, $data, $ipJson); 
     } else { 
      $data['message'] = 'Unable to retrieve review details.'; 
      $status = $this->clamo_lib->return_status('error', $serviceName, $data, $ipJson); 
     } 
     return $status; 
    }

這是我的代碼，我可以檢索具有相同名稱的單行數據。例如reviewee_name =「sangeetha」意味着我需要顯示名稱爲sangeetha的細節。但現在單行數據只有我得到我需要做的？在codeigniter的一個表中檢索多個具有相同名稱的數據

來源

2013-07-09 sangee

<?php 

//don't overwrite the array values 
function search_review($input, $serviceName){ 

    $data = array(); 

    $ipJson = json_encode($input); 
    $this->db->select('*'); 
    $this->db->from('reviews'); 
    $this->db->where('reviewee_name', $input['reviewee_name']); 
    $query = $this->db->get(); 
    $result = $query->result(); 
    if (!empty($result)) { 
     foreach ($query->result() as $row) 
     { 
      //here you're overwriting the values 
      $data[]['reviewer_id'] = $row->reviewer_id; 
      $data[]['reviewee_name'] = $row->reviewee_name; 
      $data[]['tournament_played_c_s'] = $row->tournament_played_c_s; 
     } 
     $data['message'] = 'Review details retrieved successfully.'; 
     $status = $this->clamo_lib->return_status('success', $serviceName, $data, $ipJson); 
    } else { 
     $data['message'] = 'Unable to retrieve review details.'; 
     $status = $this->clamo_lib->return_status('error', $serviceName, $data, $ipJson); 
    } 
    return $status; 
}

來源

2013-07-09 07:41:48 Sundar

謝謝很多sundar其工作正常.. – sangee

一個疑問孫大信 – sangee

' <_0> 3 <_1> deepi <_2> 奈，TN <_3> 4 <_4> deepi <_5> 卡納，成功檢索班加羅爾評分的信息。 ' – sangee

看你的代碼..我可以看到你更換相同的密鑰在數據陣列..所以這裏的問題..

試試這個

.. 
foreach ($query->result() as $row) 
{ 
     $data[]['reviewer_id'] = $row->reviewer_id; 
     $data[]['reviewee_name'] = $row->reviewee_name; 
     $data[]['tournament_played_c_s'] = $row->tournament_played_c_s; 
} 
...

此次榮獲」 t取代key.however $數據將有不同的結構（二維數組），所以只是要小心，同時顯示它..使用echo "<pre>";print_r($data);來檢查$數據結構

來源

2013-07-09 07:42:23 bipen

在codeigniter的一個表中檢索多個具有相同名稱的數據

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