2012-04-20 156 views

回答

116

從「編程的Python」由馬克·魯茨:

curs.execute("Select * FROM people") 
colnames = [desc[0] for desc in curs.description] 
+41

如果您只是想要列名稱,請不要選擇表中的所有行。這是更有效的:'curs.execute(「SELECT * FROM people LIMIT 0」)' – Demitri 2012-09-06 22:03:46

+1

值得一提的是,這對視圖和表格都有效,但它不能(很容易)從視圖獲取列名'information_schema'。 – wjv 2016-06-23 07:30:18

+1

可能更直觀地得到名稱作爲屬性: colnames = [des.desc.name用於des.c in curs.description] – dexgecko 2018-01-15 23:28:52

15

獲得一個單獨的查詢的列名,您可以查詢INFORMATION_SCHEMA.COLUMNS表。在同一個查詢的數據行

#!/usr/bin/env python3 

import psycopg2 

if __name__ == '__main__': 
    DSN = 'host=YOUR_DATABASE_HOST port=YOUR_DATABASE_PORT dbname=YOUR_DATABASE_NAME user=YOUR_DATABASE_USER' 

    column_names = [] 

    with psycopg2.connect(DSN) as connection: 
     with connection.cursor() as cursor: 
      cursor.execute("select column_name from information_schema.columns where table_schema = 'YOUR_SCHEMA_NAME' and table_name='YOUR_TABLE_NAME'") 
      column_names = [row[0] for row in cursor] 

    print("Column names: {}\n".format(column_names)) 

獲得列名,你可以使用光標的描述字段:

#!/usr/bin/env python3 

import psycopg2 

if __name__ == '__main__': 
    DSN = 'host=YOUR_DATABASE_HOST port=YOUR_DATABASE_PORT dbname=YOUR_DATABASE_NAME user=YOUR_DATABASE_USER' 

    column_names = [] 
    data_rows = [] 

    with psycopg2.connect(DSN) as connection: 
    with connection.cursor() as cursor: 
     cursor.execute("select field1, field2, fieldn from table1") 
     column_names = [desc[0] for desc in cursor.description] 
     for row in cursor: 
     data_rows.append(row) 

    print("Column names: {}\n".format(column_names)) 
-2
#!/usr/bin/python 
import psycopg2 
#note that we have to import the Psycopg2 extras library! 
import psycopg2.extras 
import sys 

def main(): 
    conn_string = "host='localhost' dbname='my_database' user='postgres' password='secret'" 
    # print the connection string we will use to connect 
    print "Connecting to database\n ->%s" % (conn_string) 

    # get a connection, if a connect cannot be made an exception will be raised here 
    conn = psycopg2.connect(conn_string) 

    # conn.cursor will return a cursor object, you can use this query to perform queries 
    # note that in this example we pass a cursor_factory argument that will 
    # dictionary cursor so COLUMNS will be returned as a dictionary so we 
    # can access columns by their name instead of index. 
    cursor = conn.cursor(cursor_factory=psycopg2.extras.DictCursor) 

    # tell postgres to use more work memory 
    work_mem = 2048 

    # by passing a tuple as the 2nd argument to the execution function our 
    # %s string variable will get replaced with the order of variables in 
    # the list. In this case there is only 1 variable. 
    # Note that in python you specify a tuple with one item in it by placing 
    # a comma after the first variable and surrounding it in parentheses. 
    cursor.execute('SET work_mem TO %s', (work_mem,)) 

    # Then we get the work memory we just set -> we know we only want the 
    # first ROW so we call fetchone. 
    # then we use bracket access to get the FIRST value. 
    # Note that even though we've returned the columns by name we can still 
    # access columns by numeric index as well - which is really nice. 
    cursor.execute('SHOW work_mem') 

    # Call fetchone - which will fetch the first row returned from the 
    # database. 
    memory = cursor.fetchone() 

    # access the column by numeric index: 
    # even though we enabled columns by name I'm showing you this to 
    # show that you can still access columns by index and iterate over them. 
    print "Value: ", memory[0] 

    # print the entire row 
    print "Row: ", memory 

if __name__ == "__main__": 
    main() 
1

我人所以曾經面臨類似的問題。我用一個簡單的技巧來解決這個問題。 假設你像

col_name = ['a', 'b', 'c'] 

然後列表有列名,你可以做以下

for row in cursor.fetchone(): 
    print zip(col_name, row) 
0

執行SQL查詢寫下面寫在2.7

total_fields = len(cursor.description)  
fields_names = [i[0] for i in cursor.description 
    Print fields_names 
3

如果你想python腳本後從db查詢命名爲obj obj,可以使用以下代碼片段:

from collections import namedtuple 

def create_record(obj, fields): 
    ''' given obj from db returns namedtuple with fields mapped to values ''' 
    Record = namedtuple("Record", fields) 
    mappings = dict(zip(fields, obj)) 
    return Record(**mappings) 

cur.execute("Select * FROM people") 
colnames = [desc[0] for desc in cur.description] 
rows = cur.fetchall() 
cur.close() 
result = [] 
for row in rows: 
    result.append(create_record(row, colnames)) 

這allowes你,好像他們是類屬性,即

record.id,record.other_table_column_name等

,甚至更短的以評估記錄值

from psycopg2.extras import NamedTupleCursor 
with cursor(cursor_factory=NamedTupleCursor) as cur: 
    cur.execute("Select * ...") 
    return cur.fetchall() 
7

你可以做的另一件事是創建一個遊標,你將能夠通過他們的名字來引用你的列(這是一個需求,導致我到這個頁面第一個地方):

import psycopg2 
from psycopg2.extras import RealDictCursor 

ps_conn = psycopg2.connect(...) 
ps_cursor = psql_conn.cursor(cursor_factory=RealDictCursor) 

ps_cursor.execute('select 1 as col_a, 2 as col_b') 
my_record = ps_cursor.fetchone() 
print (my_record['col_a'],my_record['col_b']) 

>> 1, 2