更新SQL數據庫PDO

Question

我試圖與此代碼

public function updateImprovement($id, $improveId, $body) { 

    //UPDATE ITC 
    $update = ("UPDATE as_improvement SET value = :value WHERE id = :id"); 

    $statement = $this->db-> prepare($update); 

    $statement -> bindValue(":id", $id, PDO::PARAM_STR); 
    $statement -> bindValue(":value", $body, PDO::PARAM_STR); 


    $statement -> execute(); 

    //UPDATE IMPROVE 
    $update = ("UPDATE as_improve SET content_new = :content_new AND approved = 1 WHERE id = :improveId"); 

    $statement = $this->db-> prepare($update); 


    $statement -> bindValue(":improveId", $improveId, PDO::PARAM_STR); 
    $statement -> bindValue(":content_new", $body, PDO::PARAM_STR); 



    $statement -> execute(); 

} 

的問題是在「content_new」更新一些數據庫值 - >（content_new =：content_new）變量，因爲沒有它，SQL句子完美執行。我可以在兩個句子中使用$ body兩次嗎？

Answer 1

你正在運行content_new = :content_new AND approved = 1

它應該是：content_new = :content_new, approved = 1

不過，我已經重新吉格舞這一點對你：

public function updateImprovement($id, $improveId, $body) { 

    //UPDATE ITC 
    $update = ("UPDATE as_improvement SET value = ? WHERE id = ?"); 
    $statement = $this->db-> prepare($update); 
    $statement->execute([$body, $id]); 

    //UPDATE IMPROVE 
    $update = ("UPDATE as_improve SET content_new = ?, approved = 1 WHERE id = ?"); 
    $statement = $this->db-> prepare($update); 
    $statement->execute([$body, $improveId]); 
}