2010-06-18 84 views
3

功能波紋管時被傳遞一個字符串 「1004233」,並打印輸出如下:
D1 = 1.004233
D2 = 0.00423299999999993
D3 = 4232.99999999993
D4 = 4232
C#精度損失除以雙

我需要D4打印4233而不是4232.我如何阻止這種精確度損失的發生?

public string someFunc(String s){ 
     string retval = "0"; 
     try{ 
      int id = int.Parse(s); 
      double d = (double)id/(double)1000000; 
      Console.WriteLine("D1 = " + d); 
      d = d - Math.Truncate(d); 
      Console.WriteLine("D2 = " + d); 
      d = d * (double)1000000; 
      Console.WriteLine("D3 = " + d); 
      retval = "" + Math.Truncate(d); 
      Console.WriteLine("D4 = " + retval); 
     }catch(Exception ex){} 
     return retval; 
} 

回答

12

這是standard floating-point question

改爲使用decimal
雖然decimal也沒有無限的精度,但它們是以10爲底的實現的,所以它們會給你你期望的結果。