首先是一些代碼,這是更好地提取find(:all, ...)
調用用戶模型。例如,稱它爲search
。
class User < ActiveRecord::Base
scope :search_by_email, lambda { |email|
joins(:roles).where(["name IN (?) and email like '#{email}%'",["content team","ops team"]])
}
end
使用它的控制器則:
def admin_search
@admins = User.search_by_email(params[:email]).paginate(:page => params[:page], :per_page => 10)
end
現在,你可以在隔離測試search_by_email
方法 - 檢查,這對「內容團隊」和「運營團隊」只返回結果,正確使用空電子郵件字符串等等。
我不認爲你必須測試paginate
方法,因爲它應該已經在kaminari,will_paginate或任何你使用的測試。但是如果你想確定它是否被調用,那麼你可以在控制器規格中使用模擬期望(should_receive
)。
編輯:怎樣的規格可能看起來像
describe User do
describe ".search_by_email" do
let(:content_team) { Role.create! name: "content team" }
let(:ops_team) { Role.create! name: "ops team" }
let(:another_team) { Role.create! name: "another team" }
it "should search in content team" do
content_team_user = User.create! email: "[email protected]", roles: [content_team]
User.search_by_email("black").should == [content_team_user]
end
it "should search in ops team" do
ops_team_user = User.create! email: "[email protected]", roles: [ops_team]
User.search_by_email("black").should == [ops_team_user]
end
it "should not search in other teams" do
other_team_user = User.create! email: "[email protected]", roles: [another_team]
User.search_by_email("black").should == []
end
it "should not search by empty string" do
content_team_user = User.create! email: "[email protected]", roles: [content_team_user]
User.search_by_email("").should == []
User.search_by_email(nil).should == []
end
# more specs for search...
end
end
describe UsersController do
describe "admin search" do
let(:admin_user) { double(:admin_user).as_null_object }
let(:search_string) { 'joe' }
it "should search for admin users" do
User.should_receive(:search_by_email).with(search_string).and_return([admin_user])
get :admin_search, email: search_string
assigns(:admins).should == [admin_user]
end
end
end
我是新的RSpec的來寫,u能告訴我怎麼寫rspec的 – Swathi 2012-04-10 13:07:59
好吧,我會更新我的答案 – cutalion 2012-04-11 01:09:40