其中包含的Java

Question

我有休耕電子郵件ID非英語（UTF-8）字符驗證電子郵件地址

閃閃發光@閃閃發光.com 

我需要在服務器端驗證這種類型的電子郵件，使用戶無法進入該類型的電子郵件..
我以低於regex-

/^([a-z0-9\+_\-]+)(\.[a-z0-9\+_\-]+)*@([a-z0-9\-]+\.)+[a-z]{2,6}$/gi 

但解決在JavaScript中類似的問題。無法在java.lang中做同樣的事情。請幫助我們。
在此先感謝！

Answer 1

Java的正則表達式模式(?i)[-a-z0-9+_][-a-z0-9+_.]*@[-a-z0-9][-a-z0-9.]*\\.[a-z]{2,6}應該足夠了。下面是該模式是指：

(?i)   # Case insensitive flag 
[-a-z0-9+_]  # First character 
[-a-z0-9+_.]* # Zero or more characters 
@    # Literal '@' character 
[-a-z0-9]  # Match a single character 
[-a-z0-9.]*  # Match zero or more characters 
\.    # Literal '.' character 
[a-z]{2,6}  # Match 2 through 6 alpha characters 

下面的測試代碼...

final String ps = 
     "(?i)[-a-z0-9+_][-a-z0-9+_.]*@[-a-z0-9][-a-z0-9.]*\\.[a-z]{2,6}"; 
final Pattern p = Pattern.compile(ps); 
for (String s : new String[] {"foo@bar.COM", "+foo@bar.COM", 
     "-foo@bar.COM", "fo_o@bar.COM", "f.oo@bar.COM", "a@b.cdefgh", 
     "3@4.com", "3@4.5.6-7.8.com", ".foo@bar.com", "a@b.cdefghi", 
     "閃閃發光@閃閃發光.com"}) 
{ 
    final Matcher m = p.matcher(s); 
    if (m.matches()) { 
     System.out.println("Success: " + s); 
    } else { 
     System.out.println("Fail: " + s); 
    } 
} 

... ...將輸出：

Success: foo@bar.COM 
Success: +foo@bar.COM 
Success: -foo@bar.COM 
Success: fo_o@bar.COM 
Success: f.oo@bar.COM 
Success: a@b.cdefgh 
Success: 3@4.com 
Success: 3@4.5.6-7.8.com 
Fail: .foo@bar.com 
Fail: a@b.cdefghi 
Fail: 閃閃發光@閃閃發光.com 

通過使用Matcher.matches()方法，你不需要包括^開始行或$行結束邊界匹配結構，因爲Matcher.matches()將匹配整個字符串。

Answer 2

[更新]遺憾的是js代碼。試試這個：

import java.util.regex.Matcher; 
import java.util.regex.Pattern; 


    public class EmailValidator{ 

      private Pattern pattern; 
      private Matcher matcher; 

      private static final String EMAIL_PATTERN = 
         "^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@ 
         [A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$"; 

      public EmailValidator(){ 
       pattern = Pattern.compile(EMAIL_PATTERN); 
      } 

      /** 
      * Validate hex with regular expression 
      * @param hex hex for validation 
      * @return true valid hex, false invalid hex 
      */ 
      public boolean validate(final String hex){ 

       matcher = pattern.matcher(hex); 
       return matcher.matches(); 

      } 
    }