的Python：捕獲從subprocess.call的輸出與標準輸出

Question

所以我嘗試輸出保存從我subprocess.call，但我不斷收到以下錯誤： AttributeError: 'int' object has no attribute 'communicate'

代碼如下：

p2 = subprocess.call(['./test.out', 'new_file.mfj', 'delete1.out'], stdout = PIPE) 
output = p2.communicate[0] 

Answer 1

您正在尋找subprocess.Popen()而不是call()。您還需要將其更改爲p2.communicate()[0]。

Answer 2

這是因爲subprocess.call返回一個int：

subprocess.call(args, *, stdin=None, stdout=None, stderr=None, shell=False) 

    Run the command described by args. Wait for command to complete, then return the returncode attribute. 

它看起來像你想subprocess.Popen().

下面是一段典型的代碼一塊，我必須這樣做：

p = Popen(cmd, stdout=PIPE, stderr=PIPE, bufsize=256*1024*1024) 
output, errors = p.communicate() 
if p.returncode: 
    raise Exception(errors) 
else: 
    # Print stdout from cmd call 
    print output 

Answer 3

您應該使用子過程

try:    
     subprocess.check_output(['./test.out', 'new_file.mfj', 'delete1.out'], shell=True, stderr=subprocess.STDOUT) 
    except subprocess.CalledProcessError as exception: 
     print exception.output