我試圖測試一些算法,並計時它們,如果它們花費太長時間(準確地說60秒),我想停止它們。我已經試着擺弄時鐘功能,但我似乎無法讓它停下來,並轉向下一個測試。我想這樣做而不編輯isUnique函數本身。有沒有辦法通過從開始計時操作並在經過60秒後停止操作?以下是節目至今..在設定的時間量後停止功能並轉到下一個功能
#include "stdafx.h"
#include <iostream>
#include <vector>
#include <ctime>
#include <chrono>
#include <cstdlib>
#include <random>
#include <algorithm>
using namespace std;
bool isUnique(const vector<int>& arr, int start, int end) {
if (start >= end) return true;
if (!isUnique(arr, start, end - 1))
return false;
if (!isUnique(arr, start + 1, end))
return false;
return (arr[start] != arr[end]);
}
bool isUniqueLoop(const vector<int>& arr, int start, int end) {
if (start >= end) return true;
for (int i = start; i < end; i++)
for (int j = i + 1; j <= end; j++)
if (arr[i] == arr[j])return false;
return true;
}
bool isUniqueSort(const vector<int>& arr, int start, int end) {
if (start <= end) return true;
vector<int> buf(arr);
sort(buf.begin() + start, buf.begin() + end);
for (int i = start; i < end; i++)
if (buf[i] == buf[i + 1]) return false;
return true;
}
int main() {
int max = 0;
cout << "Enter a number for the Max range: ";
cin >> max;
default_random_engine randGen(time(0));
uniform_int_distribution<int> randNum(0, max);
int i;
int j;
int n = randNum(randGen);
int m = n;
double timeout = 60.0;
vector<int> myVect;
for (i = 0; i <= m; i++) {
myVect.push_back(randNum(randGen));
//cout << myVect[i] << endl;
}
cout << "Recursive Algorithm Test... " << endl;
cout << endl;
// recursive algorithm
clock_t start = clock();
isUnique(myVect, 0, m);
if (isUnique(myVect, 0, m) == true) {
cout << "The Vector is Unique! " << endl;
}
else {
cout << "The Vector is not Unique! " << endl;
}
clock_t end = clock();
double time = (double)(end - start)/CLOCKS_PER_SEC * 1000.0;
cout << "CPU Time used for this algorithm: " << time << " ms" << endl;
if (time > 60000) {
cout << "This function takes too long! " << endl;
}
cout << "------------------------------------" << endl;
cout << "Iterative Algorithm Test... " << endl;
cout << endl;
// iterative algorithm
clock_t start2 = clock();
isUniqueLoop(myVect, 0, n);
if (isUniqueLoop(myVect, 0, n) == true) {
cout << "The Vector is Unique! " << endl;
}
else {
cout << "The Vector is not Unique! " << endl;
}
clock_t end2 = clock();
double time2 = (double)(end2 - start2)/CLOCKS_PER_SEC * 1000.0;
cout << "CPU time used for this algorithm: " << time2 << " ms. " << endl;
if (time2 > 60000) {
cout << "This function takes too long! " << endl;
}
cout << "------------------------------------" << endl;
cout << "Sort Algorithm Test... " << endl;
cout << endl;
// sort algorithm
clock_t start3 = clock();
isUniqueSort(myVect, 0, n);
if (isUniqueSort(myVect, 0, n) == true) {
cout << "The Vector is Unique! " << endl;
}
else {
cout << "The Vector is not Unique " << endl;
}
clock_t end3 = clock();
double time3 = (double)(end3 - start3)/CLOCKS_PER_SEC * 1000.0;
cout << "CPU time used for this algorithm: " << time3 << " ms. " << endl;
if (time3 > 60000) {
cout << "This function takes too long! " << endl;
}
cout << endl;
system("pause");
return 0;
第一isUnique設置()函數總是需要很長的,因爲它的無效和遞歸,這很好,它應該是這樣的。但是,我不知道如何終止這個特定的功能,並且如果它需要很長時間才能轉到下一個功能。對羅嗦的帖子感到抱歉。有什麼建議麼?
是什麼問題? – amit
如何使用該算法找到n的最大值,以便算法在一分鐘或更短時間內運行? –
(1)嘗試'n'的各種值。 (2)「運行一分鐘或更少」是有點機器(和編譯器)具體... – amit