陣列在bash shell腳本

Question

#!/bin/sh 
# Script to count the total in an array 
# Define the name of the file 
# 
fname=names.txt 

# Read in the contact details from the keyboard 
echo "Please enter the following contact details:" 
echo 
echo "Given name: \c" 
read name 
echo " value: \c" 
read value 
# Write the details to the text file 
echo $name:$value >> $fname 

我試圖代碼在bash腳本什麼的，我有一個txt文件，我進入了它的名稱如下如

lex +7.5 
creg +5.3 
xondr/xonde +1.5 
gloria-1 
lex +7.5 
gloria -1 
creg +5.3 
xondr/xonde +1.5 
lex +7.5 
#and so on 

我希望有一個代碼或環當我運行該程序時，它應該顯示在txt文件上的名稱，並顯示總數，如果lex出現7次，凱萊3次，它會顯示lex 52.5 gloria-3等。我不知道你是否得到我的想法...

Answer 1

#!/usr/bin/env bash 

awk '{people[$1] += $2} END {for (person in people) 
{ printf("%s %10.2f\n",person,people[person])}}' test.txt 

Answer 2

聽起來像你想要的東西：

 
$ awk '{x[$1] += $2} END {for(i in x) print i, x[i]}' input-file 

Answer 3

#!/bin/bash 
declare -A names 
declare name num 

#sum 
while IFS=" " read name num; do 
    names[$name]=$(bc <<< "${names[$name]:-0}$num") 
done 

#print 
for name in ${!names[@]}; do 
    echo "$name: ${names[$name]}" 
done 

是這樣的嗎？取決於兩個由空格分開的字段，而數字前加+或 - 。