1
是像下面的boost :: MPL ::類型和字符的字符串的地圖
typedef boost::mpl::map<
pair<int,"int">
, pair<long,"long">
, pair<bool,"bool">
> m;
可能嗎?如果不是,有什麼選擇?
是像下面的boost :: MPL ::類型和字符的字符串的地圖
typedef boost::mpl::map<
pair<int,"int">
, pair<long,"long">
, pair<bool,"bool">
> m;
可能嗎?如果不是,有什麼選擇?
如果你可以使用C++編譯器14(目前僅鏘> = 3.5),你可以使用Boost.Hana:
#include <boost/hana.hpp>
namespace hana = boost::hana;
auto m = hana::make_map(
hana::make_pair(hana::type_c<int>, BOOST_HANA_STRING("int")),
hana::make_pair(hana::type_c<long>, BOOST_HANA_STRING("long")),
hana::make_pair(hana::type_c<bool>, BOOST_HANA_STRING("bool"))
);
// These assertions are done at compile-time
BOOST_HANA_CONSTANT_ASSERT(m[hana::type_c<int>] == BOOST_HANA_STRING("int"));
BOOST_HANA_CONSTANT_ASSERT(m[hana::type_c<long>] == BOOST_HANA_STRING("long"));
BOOST_HANA_CONSTANT_ASSERT(m[hana::type_c<bool>] == BOOST_HANA_STRING("bool"));
如果你也願意使用支持非標準的GNU擴展(至少)由鐺和GCC,你甚至可以做以下的拖放醜陋BOOST_HANA_STRING
宏:
#define BOOST_HANA_CONFIG_ENABLE_STRING_UDL
#include <boost/hana.hpp>
namespace hana = boost::hana;
using namespace hana::literals;
constexpr auto m = hana::make_map(
hana::make_pair(hana::type_c<int>, "int"_s),
hana::make_pair(hana::type_c<long>, "long"_s),
hana::make_pair(hana::type_c<bool>, "bool"_s)
);
static_assert(m[hana::type_c<int>] == "int"_s, "");
static_assert(m[hana::type_c<long>] == "long"_s, "");
static_assert(m[hana::type_c<bool>] == "bool"_s, "");
我想你想一個'提振::融合:: map'。我猜'boost :: mpl :: string'作爲'boost :: mpl :: pair'中的第二個參數也可以。 – llonesmiz