我寫的獲取從數據庫字段此下面功能,但它不工作:我在函數中編寫數據庫提取代碼,但它不起作用?
function Refresh_TBL_post() {
global $conn;
#DB Query Comment
$stmt = $conn->prepare("SELECT * FROM post WHERE id=? ");
$stmt->bind_param("s", $_REQUEST['editpostId']);
#Run Query In DB
$stmt->execute();
#Get Count Of Rows
#Refrsh $stmt
$stmt->get_result();
$row = $stmt->fetch_assoc();
return $row;
}
我呼籲這樣Refresh_TBL_post();
此功能,但它沒有工作。我該如何解決它?
_ $ stmt = $ stmt-> get_result()_? –
是的,它是錯的? –
錯誤日誌中引發的任何錯誤,檢查錯誤? http://php.net/manual/en/mysqli.error.php – chris85