如何創建一個休眠獨特的查詢

Question

我已經看了一下網絡，無法真正找到明確的答案。

我有兩個表A和B. B是A的孩子，我需要得到基於A.

的一些限制，例如的B不同的屬性列表：

SQL：

select distinct sirm.attribute 
from store_item_received_material sirm 
where sirm.store_item_id in (select si.id from store_item si where si.program_id = 9 and si.customer_id = 1 and si.date_processed is not null); 

當然，SQL的工作很好。

現在，我需要在我的項目中運行這個。

我正在運行hibernate 3.3.1。我試過如下：

@NamedNativeQueries ({ 
    @NamedNativeQuery (name = "select.distinct.sirm.for.customer.program", query = "select distinct(sirm.attribute) as attribute from store_item_received_material as sirm where sirm.store_item_id in (select si.id from store_item as si where si.customer_id = ? and si.program_id = ? and si.date_processed is not null)") 
}) 

但失敗，出現以下錯誤：

嵌套的例外是org.hibernate.cfg.NotYetImplementedException：純天然的標量的查詢尚不支持

所以，我想如下：

@NamedNativeQueries ({ 
    @NamedNativeQuery (name = "select.distinct.sirm.for.customer.program", query = "select distinct(sirm.attribute) as attribute from store_item_received_material as sirm where sirm.store_item_id in (select si.id from store_item as si where si.customer_id = ? and si.program_id = ? and si.date_processed is not null)", resultClass=StoreItemReceivedMaterial.class) 
}) 
@SqlResultSetMapping(name = "select.distinct.sirm.for.customer.program", entities=@EntityResult(entityClass = StoreItemReceivedMaterial.class)) 

但是，由於該對象是一個實體對象，並沒有一個ID列，所以不起作用。

那麼，如何做到這一點

Answer 1

對於您需要的結果集定義與@ColumnResult標查詢任何幫助：

@NamedNativeQueries ({ 
    @NamedNativeQuery (name = "select.distinct.sirm.for.customer.program", 
     query = "select distinct(sirm.attribute) as attribute from store_item_received_material as sirm where sirm.store_item_id in (select si.id from store_item as si where si.customer_id = ? and si.program_id = ? and si.date_processed is not null)", resultSetMapping = "select.distinct.sirm.for.customer.program" }) 

@SqlResultSetMapping(name = "select.distinct.sirm.for.customer.program", 
    columns = @ColumnResult(name = "attribute"))