2
我正在嘗試用光標編寫mySQL過程來計算票價。我通過stationid,然後我找出他們在哪個區域。票價是1美元的設定值,並且每個區域的額外費用爲0.20美元。 我到目前爲止的代碼已經運行,但是遊標存在問題將值提取到變量中。mySQL存儲過程 - 光標錯誤
任何幫助將不勝感激。由於
表:
DROP DATABASE IF EXISTS luasSystem;
CREATE DATABASE luasSystem;
USE luasSystem;
CREATE TABLE IF NOT EXISTS line
(
line_id INT NOT NULL AUTO_INCREMENT,
Line_colour CHAR(10) NOT NULL,
PRIMARY KEY (line_id)
) ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS zone
(
zone_id INT NOT NULL AUTO_INCREMENT,
zone_name VARCHAR(20) NOT NULL,
line INT NOT NULL,
PRIMARY KEY (zone_id),
FOREIGN KEY (line) REFERENCES line(line_id) ON UPDATE CASCADE ON DELETE RESTRICT
) ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS station
(
station_id INT NOT NULL AUTO_INCREMENT,
station_name CHAR(20) NOT NULL,
service CHAR(20),
line INT NOT NULL,
zone INT NOT NULL,
PRIMARY KEY (station_id),
FOREIGN KEY (line) REFERENCES line(line_id) ON UPDATE CASCADE ON DELETE RESTRICT,
FOREIGN KEY (zone) REFERENCES zone(zone_id) ON UPDATE CASCADE ON DELETE RESTRICT
) ENGINE=InnoDB;
存儲過程:你使用十進制值,而不是整數
DROP PROCEDURE IF EXISTS calculateFare;
DELIMITER //
CREATE PROCEDURE calculateFare
(
IN stationid1 INT, IN stationid2 INT
)
BEGIN
DECLARE zoneNum1 INT;
DECLARE zoneNum2 INT;
DECLARE num INT;
DECLARE fare DOUBLE;
DECLARE tableEnd BOOLEAN;
DECLARE zoneCur CURSOR FOR
SELECT zone, zone FROM station
WHERE station_name = stationid1 AND station_name = stationid2;
DECLARE CONTINUE HANDLER FOR NOT FOUND
SET tableEnd = TRUE;
OPEN zoneCur;
the_loop: LOOP
FETCH zoneCur
INTO zoneNum1, zoneNum2;
IF tableEnd THEN
CLOSE zoneCur;
LEAVE the_loop;
END IF;
SET fare = 1;
SET num = 0;
IF zoneNum1 < zoneNum2 THEN
SET num = zoneNum2 - zoneNum1;
ELSEIF zoneNum1 > zoneNum2 THEN
SET num = zoneNum1 - zoneNum2;
END IF;
SET fare = (num * 0.20) + 1;
SELECT fare;
END LOOP the_loop;
END //
DELIMITER ;
CAll calculateFare(3,5);
這看起來很奇怪(你的意思是把它們命名爲相同?):SELECT zone,zone FROM station WHERE station_name = stationid1 AND station_name = stationid2; – ethrbunny 2013-04-05 20:51:19
嗨,感謝您的回覆。我試圖讓這兩個電臺「stationid1」和「stationid2」的區域,它不會允許我做多個選擇語句。 – d199224 2013-04-05 20:55:50
除非兩個'stationid'值相等,否則這將永遠不會返回任何內容。你正在和這兩個條款。 – ethrbunny 2013-04-05 20:58:24